10t = b - 4
12b+8t = $348
This is a system of equations. I’ll be solving through substitution.
In the first equation. solving for b (the easier variable to isolate) gives you:
b = 10t + 4
Substitute this into the second equation:
12(10t+4) +8t = 348
120t+48+8t = 348
128t = 300
t = 2.34375 —> round it to the nearest cent to get 2.34 dollars
b = 10t+4
b = 10(2.34)+4
b = 27.4 dollars
Answer:
k=20
Step-by-step explanation:
when x approaches 4, the denominator x-4 approaches 0
if the denominator is 0, it means that this is invalid
if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit
so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4
so x^2 + x - k = 0 when x = 4
4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20
Answer:
![4500 = 1200 + 300m](https://tex.z-dn.net/?f=4500%20%3D%201200%20%2B%20300m)
Step-by-step explanation:
Given
![Total = 4500](https://tex.z-dn.net/?f=Total%20%3D%204500)
![Base\ Amount = 1200](https://tex.z-dn.net/?f=Base%5C%20Amount%20%3D%201200)
monthly
Required
Write an expression to determine the number of months
The total can be expressed using:
![Total = Base\ Amount +Payment * Number\ of\ months](https://tex.z-dn.net/?f=Total%20%3D%20Base%5C%20Amount%20%2BPayment%20%2A%20Number%5C%20of%5C%20months)
Substitute value for each term
![4500 = 1200 + 300 * m](https://tex.z-dn.net/?f=4500%20%3D%201200%20%2B%20300%20%2A%20m)
![4500 = 1200 + 300m](https://tex.z-dn.net/?f=4500%20%3D%201200%20%2B%20300m)
Hence:
Option F answers the question
Answer:
i) 3/4
ii) 1/3
iii) 1/3
iv) 5/6 cents
Step-by-step explanation:
Any ratio can be written as a fraction.
For example 3:4 can be writen as 3/4 or 14:42 as 14/42.
After you convert them to fractions you then simplify them by finding their highest common factor (HCF) and then divide both numerator and denominator by the HCF. When you cant simplify the fraction anymore, that is the fraction in its lowest terms.