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2 years ago

PLS HELP IF U CAN where is the graph increasing? options: x<0 or x>0

Mathematics

1 answer:

boyakko [2]2 years ago

5 0

Answer:

x>0

Sorry to say this but im speechless when I read the question

no hard feelings

keep studying

Step-by-step explanation:

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The algebraic expression for "the quotient of 73 and x" is

lyudmila [28]

Answer

it could be 73/x

Step-by-step explanation:

3 0

3 years ago

PLEASE HELP!! BRAINILIESTTTT

Andrei [34K]

Answer:

The element is Boron(B)

Step-by-step explanation:

This is because on the periodic table, it shows that Boron has 5 protons and 5 electrons

5 0

2 years ago

Subtract -13xy from -5xy so -5xy -(-13xy)=?

S_A_V [24]

Answer:

8xy

Step-by-step explanation:

Subtract -13xy from -5xy

-5xy - (-13xy) =

-5xy + 13xy =

8xy

good luck, i hope this helps:)

3 0

2 years ago

Read 2 more answers

What is the measurement of angle Z. A)90∘ B)125∘ C)35∘ D)155∘

Andreyy89

Can’t answer without an image of the angle, sorry

7 0

2 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, MOE = 0.04.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601$

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, MOE = 0.02.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401$

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0

3 years ago