Given:
Annual interest rate = r%
Growth factor : x = 1 + r
The below function gives the amount in the account after 4 years when the growth factor is x .
![A(x)=800x^4+350x^3+500x^2+600x](https://tex.z-dn.net/?f=A%28x%29%3D800x%5E4%2B350x%5E3%2B500x%5E2%2B600x)
To find:
The total amount in the account if the interest rate for the account is 3% each year and initial amount.
Solution:
Rate of interest = 3% = 0.03
Growth factor : x = 1 + 0.03 = 1.03
We have,
![A(x)=800x^4+350x^3+500x^2+600x](https://tex.z-dn.net/?f=A%28x%29%3D800x%5E4%2B350x%5E3%2B500x%5E2%2B600x)
Substitute x=1.03 in the given function, to find the total amount in the account if the interest rate for the account is 3% each year.
![A(1.03)=800(1.03)^4+350(1.03)^3+500(1.03)^2+600(1.03)](https://tex.z-dn.net/?f=A%281.03%29%3D800%281.03%29%5E4%2B350%281.03%29%5E3%2B500%281.03%29%5E2%2B600%281.03%29)
![A(1.03)=800(1.12550881)+350(1.092727)+500(1.0609 )+618](https://tex.z-dn.net/?f=A%281.03%29%3D800%281.12550881%29%2B350%281.092727%29%2B500%281.0609%0A%29%2B618)
![A(1.03)=900.407048+382.45445+530.45+618](https://tex.z-dn.net/?f=A%281.03%29%3D900.407048%2B382.45445%2B530.45%2B618)
![A(1.03)=2431.311498 ](https://tex.z-dn.net/?f=A%281.03%29%3D2431.311498%0A)
![A(1.03)\approx 2431.31 ](https://tex.z-dn.net/?f=A%281.03%29%5Capprox%202431.31%0A)
Therefore, the total amount in the account is 2431.31 if the interest rate for the account is 3% each year.
For initial amount the rate of interest is 0.
Growth factor : x = 1 + 0 = 1
Substitute x=0 in the given function to find the initial amount.
![A(1)=800(1)^4+350(1)^3+500(1)^2+600(1)](https://tex.z-dn.net/?f=A%281%29%3D800%281%29%5E4%2B350%281%29%5E3%2B500%281%29%5E2%2B600%281%29)
![A(1)=800+350+500+600](https://tex.z-dn.net/?f=A%281%29%3D800%2B350%2B500%2B600)
![A(1)=2250](https://tex.z-dn.net/?f=A%281%29%3D2250)
Therefore, 2250 was put into the account at the beginning.
Answer:
b
Step-by-step explanation:
Answer:
1) m<BFD is a triangle
2) AC is a line segment
Step-by-step explanation: