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3 years ago

Using the table below, what percent of homes use electric to heat their homes and live inside city limits?

Mathematics

2 answers:

Ket [755]3 years ago

8 0

Answer:

21%

Step-by-step explanation:

To find what percent a number (Number A) is of another number (Number B), you divide Number A by Number B. Then you move the decimal point two places to the right.

35 / 165 = 0.21212121212

Move the decimal over.

21.212121212

Round it.

Artist 52 [7]3 years ago

5 0

B- 21 percent of homes

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(25pts) Due soon! Help!

navik [9.2K]

Answer:

true

True

False

Step-by-step explanation:

a. The problem tells me that for every 3 parts of red paint, I have 8 parts of yellow paint. To find the ratio of 1 part of yellow paint I can write the following statement

For 8 parts of yellow paint ------------ 3 parts of red paint

1 part of yellow paint ------------- x

So $x=\frac{1 part of yellow paint * 3 parts of red paint }{8 parts of yellow paint}$

$x= \frac{3}{8} parts of red paint$

b, I have the following relationship

3 parts of red paint ----- 8 parts of yellow paint

If I multiply the entire expression by 3 I have left

3 * 3 parts of red paint -------- 8 * 3 parts of yellow paint

9 parts of red paint ---------- 24 parts of yellow paint

c.I have the same relationship

3 parts of red paint ----- 8 parts of yellow paint

If I multiply the entire expression by 1/2 I have left

3/2 parts of red paint -------- 8/2 parts of yellow paint

3/2 parts of red paint ---------- 4 parts of yellow paint

as 3/2 is different from 10, then the approach is false

d. observing the relation of part a,

For 3 parts of red paint ------------ 8 parts of yellow paint

1 part of red paint ------------- x

So $x=\frac{1 part of red paint * 8 parts of yellow paint }{3 parts of red paint}$

$x= \frac{8}{3} parts of yellow paint$ that is different than 3/8 parts of yellow paint, then the approach is false

6 0

3 years ago

Read 2 more answers

Solve for n:<br> (n+4)/10 = (n-8)/2

nalin [4]

Answer:

n=11

Step-by-step explanation:

(n+4)/10 = (n-8)/2

We can solve using cross products

(n+4) * 2 = 10 * ( n-8)

Distribute

2n+8 = 10n -80

Subtract 2n from each side

2n+8-2n = 10n-80-2n

8 = 8n-80

Add 80 to each side

8+80= 8n-80+80

88 = 8n

Divide each side by 8

88/8 = 8n/8

11 = n

4 0

1 year ago

Read 2 more answers

Please please help!!

shepuryov [24]

Answer:

$\large\boxed{x=0\ and\ x=\pi}$

Step-by-step explanation:

$\tan^2x\sec^2x+2\sec^2x-\tan^2x=2\\\\\text{Use}\ \tan x=\dfrac{\sin x}{\cos x},\ \sec x=\dfrac{1}{\cos x}:\\\\\left(\dfrac{\sin x}{\cos x}\right)^2\left(\dfrac{1}{\cos x}\right)^2+2\left(\dfrac{1}{\cos x}\right)^2-\left(\dfrac{\sin x}{\cos x}\right)^2=2\\\\\left(\dfrac{\sin^2x}{\cos^2x}\right)\left(\dfrac{1}{\cos^2x}\right)+\dfrac{2}{\cos^2x}-\dfrac{\sin^2x}{\cos^2x}=2$

$\dfrac{\sin^2x}{(\cos^2x)^2}+\dfrac{2-\sin^2x}{\cos^2x}=2\\\\\text{Use}\ \sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-(1-\cos^2x)}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-1+\cos^2x}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{1+\cos^2x}{\cos^2x}=2$

$\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{(1+\cos^2x)(\cos^2x)}{(\cos^2x)^2}=2\qquad\text{Use the distributive property}\\\\\dfrac{1-\cos^2x+\cos^2x+\cos^4x}{\cos^4x}=2\\\\\dfrac{1+\cos^4x}{\cos^4x}=2\qquad\text{multiply both sides by}\ \cos^4x\neq0\\\\1+\cos^4x=2\cos^4x\qquad\text{subtract}\ \cos^4x\ \text{from both sides}\\\\1=\cos^4x\iff \cos x=\pm\sqrt1\to\cos x=\pm1\\\\ x=k\pi\ for\ k\in\mathbb{Z}\\\\\text{On the interval}\ 0\leq x$