Using the combination formula, it is found that the number of ways to choose the presenters is given by:
C. 462.
The order in which the presents are chosen is not important, hence the <em>combination formula</em> is used to solve this question.
<h3>What is the combination formula?</h3>
is the number of different combinations of x objects from a set of n elements, given by:

In this problem, 6 students are chosen from a set of 11, hence the number of ways is given by:

More can be learned about the combination formula at brainly.com/question/25821700
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The decision rule for rejecting the null hypothesis, considering the t-distribution, is of:
- |t| < 1.9801 -> do not reject the null hypothesis.
- |t| > 1.9801 -> reject the null hypothesis.
<h3>What are the hypothesis tested?</h3>
At the null hypothesis, it is tested if there is not enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means is of zero, hence:

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means different of zero, hence:

We have a two-tailed test, as we are testing if the mean is different of a value.
Considering the significance level of 0.05, with 75 + 46 - 2 = 119 df, the critical value for the test is given as follows:
|t| = 1.9801.
Hence the decision rule is:
- |t| < 1.9801 -> do not reject the null hypothesis.
- |t| > 1.9801 -> reject the null hypothesis.
More can be learned about the t-distribution in the test of an hypothesis at brainly.com/question/13873630
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After you've calibrated the sprayer to know your application rate in gallons per acre, divide that number into the gallons applied with each tankful to find how many acres each tankful covers. Then, multiply the acres per tank by the herbicide needed per acre to find the herbicide to put in each tankful.
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If it's a geometric sequence then:

We calculate the fourth and fifth term of the sequence:

Answer:
In year 4 15.1875 animals.
In year 5 11.390625 animals.