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3 years ago

Whats 12% in a fraction and decimal

Mathematics

2 answers:

Yuki888 [10]3 years ago

5 0

Answer : 0.12 ( decimal ) 12/100 ( fraction )

il63 [147K]3 years ago

3 0

12 percent is equal to .12 and 12/100

Have a great day!

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D=(107-115)^2+(-49+-69)^2

ladessa [460]

Answer:

d=13988 or d=1.3988 x 10^4

Step-by-step explanation:

d=(-8)^2+(-118)^2

d=64+13924

d=13988

6 0

2 years ago

Ou have found a house that you would like to purchase. The amount of the home is $225,000. You would like to finance the home th

Tpy6a [65]

Answer:

A. $22,500

Step-by-step explanation:

10% = 10/100 = 1/10

To divide a decimal number by 10, move the decimal point one place to the left (remove a zero):

$225000./10 = $22500.0 = $22500

5 0

3 years ago

Kyle went to the store to purchase a hat. The hat’s normal price is $50, but he used a coupon which allowed him to save $20. Wha

tiny-mole [99]

Answer:

Kyle saves 40 percent

$50 is 100% of what he had

$20 would be 40%

50= 100

40= 80

30= 60

20= 40

10= 20

do what u will with that info I'm bad at wording things

4 0

2 years ago

Dana has $25, she went to the store and spent $10. She then received $50 for a birthday present. Dana was excited until she real

MissTica

Dana:

Starts with 25 = 25

Spends 10 = 25 - 10 = 15

Received 50 = 15 + 50 = 65

New tires cost 75 = 65 - 75 = -10

Tracey:

Starts with 50 = 50

Gets gas for 25 = 50 - 25 = 25

Received 100 = 25 + 125 = 125

Purchased boots for 150 = 125 - 150 = -25

Tracey ends up with the least amount of money after their purchases.

Hope this helps! :)

8 0

3 years ago

Read 2 more answers

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm

GuDViN [60]

Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

$P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}$

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

$P(x \ \textless \ 3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \ 3) \approx 0.00951836732 }
$

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.

5 0

3 years ago