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maria [59]
3 years ago
8

Use elimination to solve each system of equations: 6x + 5Y = 4 6x - 7y = -20

Mathematics
1 answer:
Zepler [3.9K]3 years ago
7 0
<span>tep  1  :</span>Equation of a Straight Line

<span> 1.1 </span>    Solve  <span> 6x+5y-4 </span> = 0 

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK). 

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

<span>In this formula :

</span><span>y </span>tells us how far up the line goes
<span>x </span>tells us how far along
<span>m </span>is the Slope or Gradient i.e. how steep the line is
<span>b </span>is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the<span> line properties.</span> We shall now graph the line <span> 6x+5y-4  = 0</span> and calculate its properties

Graph of a Straight Line :<span> </span>Calculate the Y-Intercept :

Notice that when x = 0 the value of y is 4/5 so this line "cuts" the y axis at y= 0.80000

  y-intercept = 4/5 = 0.80000 Calculate the X-Intercept :

When y = 0 the value of x is 2/3 Our line therefore "cuts" the x axis at x= 0.66667

  x-intercept = 4/6 = 2/3 = 0.66667 Calculate the Slope :

Slope is defined as the change in y divided by the change in x. We note that for x=0, the value of y is 0.800 and for x=2.000, the value of y is -1.600. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of -1.600 - 0.800 = -2.400 in y. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

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Please I need help ASAP<br>pls explain your answer ​
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Answer:

47.62 cm

Step-by-step explanation:

ABCD is a rhombus. Each side measures 15 cm.

m<A = 60°.

Here are some properties of a rhombus:

Opposite angles of a rhombus are congruent.

m<C = m<A = 60°

m<ADC = m<ABC

The sum of the measures of the interior angles of a quadrilateral is 360°.

The diagonals are perpendicular bisectors of each other.

m<A + m<C + m<ADC + m<ABC = 360°

60° + 60° + 2m<ADC = 360°

2m<ADC = 240°

m<ADC = 120°

Each diagonal of a rhombus bisects a pair of congruent, opposite angles.

m<ADB + m<CDB = m<ADC

m<ADB = m<CDB

m<ADB + m<ADB = 120°

m<ADB = 60°

Triangle ABD had two angles, <A and <ADB, that measure 60°. Therefore, the third angle, <ABD also measures 60°. That makes triangle ABD an equilateral triangle.

Draw segment AT.

T is the midpoint of BD. The segment AT is the perpendicular bisector of segment BD. Triangle ATD is a 30-60-90 triangle.

Using the ratio of the lengths of the sides of a 30-60-90 triangle, we can calculate the length of AT which is the radius of circle A.

TD : AT : AD

1    : √3 :   2

AD = 15 cm

TD = AD/2

AT = √3 × TD

AT = (AD√3)/2

AT = 7.5√3 = 12.99

AQ = 12.99

perimeter = QD + PB + m(arc)PTQ + BC + CD

perimeter = (15 - 12.99) + (15 - 12.99) + 60°/360° × 2π(12.99) + 15 + 15

perimeter = 47.62

Answer: perimeter = 47.62 cm

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