<span>Plot the points a (-2,-3), b (-3,0), c (3,2), and d (4,-1). What type of quadrilateral is ABCD? Justify your answer using slope formula
the shape is a parellelogram, not a trapezoid all are parellel, but how to distinguish rhombus, rectangle, and square?</span>
6√3
Step-by-step explanation:
6 is x. side across from right angle (12) is 2x. so 6x2 to get 12. missing side is x√3. so 6√3
Answer:
To plot point A, you would count over to the left six places on the x-axis. Then, count up two places on the y-axis.
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0
As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81
Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2
So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2
A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.
3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.
So 2k^2 = 9 + 3k have two rational solutions (Option B).
Hope this Helps! :)
Answer:
y=4
x=-3
Step-by-step explanation:
4(-3)-9y=-48
-12-9y=-48
-9y=-36
y=4
x=-3
