Can someone please help me on question 25?

Find the distance CD rounded to the near

DanielleElmas [232]

the distance between cd rounded to the nearest tenth is ≈ 7

4 0

3 years ago

There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

3 years ago

I'm in trouble. Please solve this two questions!!

melomori [17]

Answer:

.........................

4 0

3 years ago

Read 2 more answers

How do you solve 4.75 times 2.2

Serga [27]

Answer:

10.45

Step-by-step explanation:

To solve it without the calculator:

First, you multiply 4.75 times 0.2 (0.95)

Then you multiply 4.75 times 2 (9.5)

Then you add the 2 numbers to get the answer.

0.95 + 9.5 = 10.45

With the calculator, just put in the 2 numbers and click enter!

7 0

3 years ago

Which of the following equations have no solutions?

azamat

Answer:

A, B & D

Step-by-step explanation:

Because if you subtract one of the constants from both sides then you should only have equal variables. In other words, both sides have to be identical in this situation.

33x-33= 33x + 25

33x = 33x + 58 No matter what you make x, the right will be 58 bigger than the right so there is no solution.

33x+33=33x+25

33x+8= 33x nope no solution

33x+25=33x+25

33x = 33x both sides identical so there is a solution

33x-25 = 33x +25

33x= 33x+50

4 0

3 years ago