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raketka [301]
3 years ago
15

How many moles of Fe are present in 24.6g of the compound​

Chemistry
1 answer:
miss Akunina [59]3 years ago
3 0

Answer:

Thus, we can say that 24.6 grams of Fe2O3 is equivalent to 0.15 mole of Fe2O3.

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The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release
KATRIN_1 [288]

The mass of melted gold to release the energy would be  3, 688. 8 Kg

<h3>How to determine the mass</h3>

The formula for quantity of energy is given thus;

Q = n × HF

Where n represents number of moles

HF  represents  heat of fusion

To find the number of moles, we have

235.0 = n × 12.550

number of moles = \frac{235}{12. 550} = 18. 725 moles

Note that molar mass of Gold is 197g/ mol

Let's note that;

Number of moles = mass/ molar mass

Mass = number of moles × molar mass

Mass = 18. 725 × 197

Mass = 3, 688. 8 Kg

Thus, the mass of melted gold to release the energy would be  3, 688. 8 Kg

Learn more about molar heat of fusion here:

brainly.com/question/15634085

#SPJ1

8 0
2 years ago
If a mineral contains only atoms of oxygen and metal, it is most likely
wariber [46]

Answer: If a mineral contains only atoms of oxygen and metal, it is most likely an oxide mineral.

Explanation:

5 0
3 years ago
Read 2 more answers
. What is the mass of 23.56 moles of Glucose<br> ples of Glucose - C6H1206?
GaryK [48]

Answer:

4244.48 g to the nearest hundredth.

Explanation:

The molar mass of Glucose = 6*12.011 + 12*1.008+ 6*15.999

= 180.156.

So 23.56 moles = 180.156 * 23.56 =  4244.48 g

8 0
4 years ago
How many 3-liter balloons could the 12-L helium tank pressurized to 160 atm fill? Keep in mind that an "exhausted" helium tank i
vaieri [72.5K]

Answer:

The 12L helium tank pressurized to 160 atm will fill <em>636 </em>3-liter balloons

Explanation:

It is possible to answer this question using Boyle's law:

P_1V_1=P_2V_2

Where P₁ is the pressure of the tank (160atm), V₁ is the volume of the tank (12L), P₂ is the pressure of the balloons (1atm, atmospheric pressure) And V₂ is the volume this gas will occupy at 1 atm, thus:

160atm×12L = 1atm×V₂

V₂ = 1920L

As the tank will never be empty, the volume of the gas able to fill balloons is the total volume minus 12L, thus the volume of helium able to fill balloons is:

1920L - 12L = 1908L

1908L will fill:

1908L×\frac{1balloon}{3L} = <em>636 balloons</em>

<em></em>

I hope it helps!

7 0
4 years ago
Which lists the structures, in correct order, through which light passes when it enters the eye?
Mashutka [201]

Answer:

cornea, pupil, lens, vitreous humor

8 0
3 years ago
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