<h2>
Hello!</h2>
The answer is:
The new volume will be 1 L.
<h2>
Why?</h2>
To solve the problem, since we are given the volume and the first and the second pressure, to calculate the new volume, we need to assume that the temperature is constant.
To solve this problem, we need to use Boyle's Law. Boyle's Law establishes when the temperature is kept constant, the pressure and the volume will be proportional.
Boyle's Law equation is:
So, we are given the information:
Then, isolating the new volume and substituting into the equation, we have:
Hence, the new volume will be 1 L.
Have a nice day!
Answer:
540.54 mmHg
Explanation:
We know that the partial pressure of a substance is defined as; Mole fraction * total pressure.
If the total amount of gases in the atmosphere is 100%, the mole fraction of nitrogen gas is now
78/100 = 0.78
Thus, partial pressure of nitrogen gas = 0.78 * 693 = 540.54 mmHg
Answer:
0.159 M
Explanation:
convert from mL to L then use the equation:
M1V1 = M2V2
rearrange to find M2
Answer:
The final volume is 3.07L
Explanation:
The general gas law will be used:
P1V1 /T1 = P2V2 /T2
V2 =P1 V1 T2 / P2 T1
Give the variables to the standard unit:
P1 = 345 torr = 345 /760 atm = 0.4539atm
T1 = -15°C = -15 + 273 = 258K
V1 = 3.48L
T2 = 36°C = 36+ 273 = 309K
P2 = 468 torr = 468 * 1/ 760 atm = 0.6158atm
V2 = ?
Equate the values into the gas equation, you have:
V2 = 0.4539 * 3.48 * 309 / 0.6158 * 258
V2 = 488.0877 /158.8764
V2 = 3.07
The final volume is 3.07L
For the answer to the question above, since the process is carried out at constant pressure,
<span>work = P (V1-V2) </span>
<span>= 1.3 E5 (6-12) = -7.8 E5 N.m (in this case the work is made by the system, so it is negative if work made on the system then it should be positive)</span>
