Answer:
Explanation:
Hello,
In this case, since one drop equals 0.05 mL of the given solution, for a concentration 0.02 g/mL, the grams of oleic acid in one drop turns turn out:
Best regards.
This
electronic transition would result in the emission of a photon with the highest
energy:
4p
– 2s
<span>This
can be the same with the emission of 4f to 2s which would emit energy in the
visible region. The energy in the visible region would emit more energy than in
the infrared region which makes this emission to have the highest energy.</span>
<span>60. 4Li(s) + O2(g) >>>>>>>>>>> 2Li2O(s)
moles O2 required = (84 grams Li) * (1 mol Li / 6.941 grams Li) * (1 mol O2 / 4 mol Li) = 3.026 moles O2 required.
PV = nRT, P = 1 atm, V = ?, n = 3.026 moles, R = 0.0821 L*atm/mol*K, T = 273 K
(1 atm)*(V) = (3.026 moles O2) * (0.0821 L*atm/mol*K) * (273 K)
V = 67.82 Liters is the answer.
hope this helps</span>
B............................