Answer:
4477381.7 calories/pound
Explanation:
It is given that,
When a candle burns it produced 41,300 Joules per 1 gram.
We need to convert it into calories per pound.
We know that,
1 cal = 4.184 J
⇒ 1 J = (1/4.184) cal
1 pound = 453.592 grams
⇒1 g = (1/453.592) pounds
Now,

Hence, 41,300 Joules/gram = 4477381.7 calories/pound.
<h3>
Answer:</h3>
272.43 K or -0.718°C
<h3>
Explanation:</h3>
We are given;
The initial pressure,P1 as 761 mmHg
Initial temperature, T1 as 0.00°C which is equivalent to 273.15 K
Final pressure as 759 mmHg
We are required to calculate the final temperature;
According to pressure law, the pressure of a gas and absolute temperature are directly proportional at constant volume.
That is; Pα T
Therefore, at varying pressure and temperature,

To get final temperature;



Therefore, the final temperature will be 272.43 K or -0.718°C
The answer is A
Trust. Me
Answer:
Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1
Explanation:
because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.