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lana66690 [7]
3 years ago
6

Aggregate demand is everything produced while simple demand is one good

Chemistry
1 answer:
Sati [7]3 years ago
7 0
I believe the answer is A. :)<span />
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I don't understand your question
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4 years ago
6. If 4 grams of salt is dissolved in 79 grams of water, what is the total mass of the final solution? [1 mark]
nordsb [41]

Answer:

A) 83g

Explanation:

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3 years ago
Read 2 more answers
Explain the relationship between forward and reverse
serious [3.7K]

If a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change to reestablish equilibrium. If a chemical reaction is at equilibrium and experiences a change in pressure, temperature, or concentration of products or reactants, the equilibrium shifts in the opposite direction to offset the change. This page covers changes to the position of equilibrium due to such changes and discusses briefly why catalysts have no effect on the equilibrium position.

For example, if the system is changed in a way that increases the concentration of one of the reacting species, it must favor the reaction in which that species is consumed. In other words, if there is an increase in products, the reaction quotient, Qc, is increased, making it greater than the equilibrium constant, Kc.

8 0
3 years ago
Carbon-14 has a half-life of 5,700 years.
Maksim231197 [3]

Answer:

3.106\ \text{g}

Explanation:

t_{1/2} = Half-life of carbon = 5700 years

t = Time at which the remaining mass is to be found = 10400 years

m_0 = Initial mass of carbon = 11 g

Decay constant is given by

\lambda=\dfrac{\ln2}{t_{1/2}}

Amount of mass remaining is given by

m=m_0e^{-\lambda t}\\\Rightarrow m=m_0e^{-\dfrac{\ln2}{t_{1/2}} t}\\\Rightarrow m=11e^{-\dfrac{\ln 2}{5700}\times 10400}\\\Rightarrow m=3.106\ \text{g}

The amount of the substance that remains after 10400 years is 3.106\ \text{g}.

5 0
3 years ago
A 25.888 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 73.464 g of wa
brilliants [131]

Answer:

Weight % of NH₃ in the aqueous waste  = 2.001 %

Explanation:

The chemical equation for the reaction

\\\\NH_3} + HCl -----> NH_4Cl

Moles of HCl = Molarity × Volume

= 0.1039 × 31.89 mL × \frac{1 \  L}{1000 \ mL}

= 0.0033 mole

Total mass of original sample = 25.888 g + 73.464 g

= 99.352 g

Total HCl taken for assay = \frac{10.762 \ g}{99.352 \ g}

= 0.1083 g

Moles of NH₃ = \frac{0.0033 \  mol}{0.1083}

= 0.03047 moles

Mass of NH₃ = number of  moles × molar mass

Mass of NH₃ = 0.03047 moles × 17 g

Mass of NH₃  = 0.51799

Weight % of NH₃  = \frac{0.51799 \ g}{25.888 \ g} * 100%%

Weight % of NH₃ in the aqueous waste  = 2.001 %

4 0
4 years ago
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