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soldi70 [24.7K]
2 years ago
13

Pls help!! need it fast.... I'm stuck

Mathematics
2 answers:
kirza4 [7]2 years ago
6 0

Answer:

2

Step-by-step explanation:

Use power rule first:

\[tex]\log_{10}(5^2)+\log_{10}(2^3)-\log_{10}(2)[tex]

Now use product and quotient rule (if + in front inside goes on top and if - in front inside goes on bottom)

[\tex]\log_{10}(\frac{5^22^3}{2})[tex]

Reducing inside fraction;

[\tex]\log_{10}(5^22^2)[tex]

Simplifying inside:

[\tex]\log_{10}(100)[tex]

100 is a power of 10...that is 10^2=100 so final answer is 2.

[tex]\log_{10}(100)=2[\tex]

viktelen [127]2 years ago
4 0

Answer:

So this is also going to stay the same, multiply first, divide, then you have your answer. Make sure if needed you need to round up your numbers.

Step-by-step explanation:

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Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or
WARRIOR [948]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\



\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8

compare them away.
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3 years ago
EXPLAIN THIS FORMULA PLS HELP ME ​
Rufina [12.5K]

it means

wdwedwefqwerf

5 0
2 years ago
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