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Are all multiples of 8 also multiples of 2

fomenos

Yes Example: some multiples of 8 are 8,16,24,32,40 and these are multiples of 2

7 0

3 years ago

A football field measures 120 yards long and 54 yards wide. We know that the team can fit 26 players in 5 yards by 8 yards box.

wariber [46]

Answer:

4,212 people

Step-by-step explanation:

We are given;

Dimensions of the football field are 120 yards by 54 yards
26 players can fit in a box measuring 5 yards by 8 yards

We are required to determine the number of people that can fit in the football field.

We are going to get the area of the field first;

Area = length × Width

Area of the field = 120 yards × 54 yards

= 6480 square yards

Then we get the area of the box

Area of the box = 5 yards × 8 yards

= 40 square yards

We then determine the number of boxes that can fit in the football field

Number of boxes = Area of the foot ball field ÷ Area of one box

= 6480 sq yards ÷ 40 sq yards

= 162 boxes

But, 26 people can fit in one box

Therefore,

Total number of people that can fit in the field is given by multiplying the number of boxes that can fit in the field by the number of people in a box

That is, Number of people = 26 players × 162 boxes

= 4,212 people

Therefore, the number of people that can fit in the football field is 4,212 people.

6 0

3 years ago

There is a lightning rod on top of a building. From a location 500 feet from the base of the building, the angle of elevation to

Kitty [74]

<h2>Hello!</h2>

The answer is:

The height of the lightning rod is 27.4 feet.

To solve the problem, we need to use the given information about the two points of observation, since both are related (both finish and start at the same horizontal distance) we need to write to equations in order to establish a relationship.

So, writing the equations we have:

We know that the angle of elevation from the base of the buildings is 36°

Also, we know that from the same location, the angle of elevation to the top of the lightning rod is 38°.

Using the information we have:

To the top of the building:

$tan(\alpha )=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}\\\\tan(36\°)=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}$

To the top of the lightning rod:

$tan(\alpha )=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}\\\\tan(38\°)=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}$

Now, isolating we have:

$tan(36\°)=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}\\\\DistanceToTheTopOfTheBuilding=tan(36\°)*BuildingBase \\\\DistanceToTheTopOfTheBuilding=tan(36\°)*500feet=363.27feet$

Also, we have that:

$tan(38\°)=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}\\\\DistanceToTheTopOfTheLightningRod=tan(38\°)*BuildingBase\\\\DistanceToTheTopOfTheLightningRod=tan(38\°)*500feet=390.64feet$