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saw5 [17]
3 years ago
13

The equation for a circle with center (h, k) is (x - h)2 + (y - k)2 = r2. If a circle is modeled by the equation (x - 4)2 + (y +

6)2 = 49, what is the center of the circle? A) (4, 6) B) (4, −6) C) (−4, 6) D) (−4, −6)
Mathematics
2 answers:
svp [43]3 years ago
5 0

Answer:

hjghjghjghjghjghjghmbmghkgm

Step-by-step explanation:

ghmkghmjnmghmnmbnm

tatuchka [14]3 years ago
3 0

Answer:

B (4,-6) because the - doesn't count bu the plus means the number is negative

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Find the first four nonzero terms in a power series expansion about x0 for a general solution to the given differential equation
timofeeve [1]
Answer is 68x bud thanks for lettting me ANWSER
3 0
3 years ago
What experimental of rolling a 2 or 3
kondor19780726 [428]

Answer:

Option 1: 0.32

Step-by-step explanation:

Let

P(A) be the experimental probability of getting two

And

P(B) be the experimental probability of getting three

The dice is rolled 360 times.

So the sample space is n(S) = 360

P(A) = n(A)/n(S)

= 54/360

= 0.15

And

P(B) = n(B)/n(S)

= 62/360

= 0.172

As both the events A and B are mutually exclusive,

P(A or B)  = P(A) + P(B)

= 0.15 + 0.172

=0.322

Rounding of to one decimal gives us:

0.32

So the probability of rolling a two or three is 0.32 ..

3 0
3 years ago
What does common factors mean?
bearhunter [10]
Factors are the numbers you multiply together to get another number. when you find the factors of two or more numbers, and then find some of the numbers (factors) are the same (common) you have common factors.

example: 12 and 36

12: 1x12, 2x6, 3x4
36: 1x36, 2x18, 3x12, 4x9, 6x6

the common factors in these numbers are 1, 2, 3, 4, 6 and 12

hope this helped you out!
6 0
3 years ago
The velocity of a particle moving back and forth on a line is vequalsStartFraction ds Over dt EndFraction equals6 sine (2 t )Sta
max2010maxim [7]

Answer:

s = 6 m

Step-by-step explanation:

The value of the velocity v is given as:

v = \frac{ds}{dt} = 6 sin(2t) m/s

To find s, we have to integrate and apply the initial values of s = o when t = 0:

\frac{ds}{dt} = 6 sin(2t)\\\\\int\limits^s_0 {ds} = \int\limits^t_0 {6sin(2t)} \, dt\\\\s|^s_o = -3cos(2t)|^t_o\\\\s - 0 = -3cos(2t) -(-3cos(0))\\\\s = -3cos(2t) + 3(1)\\\\s = -3cos(2t) + 3

When t = π/2, s will be:

s = -3cos(2 * π/2) + 3

s = -3cos(π) + 3

s = -3(-1) + 3

s = 3 + 3

s = 6 m

4 0
3 years ago
How do I solve it? URGANT!!!
defon

Answer:

Step-by-step explanation:

KL = JK, so ΔJKL is an isocesles triangle, then m∠J = m∠L

KL is a tangent line, so ∠JKL = 90°,

so m∠J = 45°

5 0
2 years ago
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