Answer:
The answer would be 1/6
Step-by-step explanation:
That is because 1/3 divided by 2 equals 6. Hope this helps.
Answer:
Correct answer: (x-√2)² + (y-√5)² = 3
Step-by-step explanation:
Given data: Center (x,y) = (√2,√5) and r = √3
The canonical or cartesian form of the equation of the circle is:
( x-p )² + ( y-q )² = r²
Where p is the x coordinate of the center, q is the y coordinate of the center and r is the radius of the circle.
God is with you!!!
Answer : option D
we need to find out the graph shows a mixed-degree system with exactly one solution
The solution of two graphs will be the intersection of two graphs
In the first graph,
There is no intersection of both circles, So no solution
second graph,
The circle intersects the parabola at two point, so two solution for this graph
Third graph,
The circle and line does not intersects, so no solution
Fourth graph,
Both parabola intersects at one point, so one solution for this graph
So option D has exactly one solution
It’s 360. Any shape will have a sum of 360, except for triangles, which are 180.
Answer:
-8
Step-by-step explanation:
For roots r and s, the quadratic can be factored ...
f(x) = (x -r)(x -s) = x^2 -(r+s)x +rs
Then the value of r^2+s^2 can be determined from the coefficient of x (-(r+s)) and the constant (rs) by ...
r^2 +s^2 = (-(r+s))^2 -2(rs) = (r^2 +2rs +s^2) -2rs = r^2 +s^2
Comparing this to your given equation, we have the coefficient of x as (-2m) and the constant term as (m^2+2m+3). Forming the expression ...
(x-coefficient)^2 -2(constant term)
we get ...
r^2 +s^2 = (-2m)^2 -2(m^2 +2m +3) = 2m^2 -4m -6
r^2 +s^2 = 2(m -1)^2 -8
The minimum value of this quadratic expression is where m=1 and the squared term is zero. That minimum value is -8.