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slavikrds [6]
2 years ago
7

The area of a triangular flag is 20 square centimeters. Its altitude is 2 centimeters longer than twice its base. Find the lengt

hs of the altitude and the base.
Mathematics
1 answer:
Anvisha [2.4K]2 years ago
7 0
The answer to your question is
Base: 4
Altitude: 10
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Rectangle ABCD with coordinates A(1, 1), B(4, 1), C(4, 2), and D(1, 2) dilates with respect to the origin to give rectangle A'B'
Virty [35]

Scale factor is a ratio. The correct option is C.

<h3>How are scale drawings formed?</h3>

For a particular scale drawing, it is already specified that all the measurements' some constant scaled version will be taken. For example, let the scale be K feet to s inches.

Then it means

\rm 1\:  ft : \dfrac{s}{k}\:  in.

All feet measurements will then be multiplied by s/k to get the drawing's corresponding lengths.

The length of AB can be written as,

AB = √[(1-4)²+ (1-1)²]

AB = 3

Since the length A'B' is 6 units, therefore, the scale factor will be,

Scale factor = (Length after transformation)/(Length before transformation)

Scale factor = 6 /3 = 2

Hence, the correct option is C.

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2 years ago
Find the missing side of the triangle​
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12

Step-by-step explanation:

Use pythag to solve.

x^2+5^2=13^2

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An art teacher gives a total of 25 pounds of clay to her students. She gives each of her 12 students the same amount of clay. Ho
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What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?
Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

AB = \sqrt{(11-4)^{2}+(3-3)^{2}}

AB = \sqrt{(7)^{2}+(0)^{2}}

AB = \sqrt{49}

\sqrt{49} =7

AB = 7 units

As take B(11, 3) to C (11, 9).

BC = \sqrt{(11-11)^{2}+(9-3)^{2}}

BC = \sqrt{(0)^{2}+(6)^{2}}

BC = \sqrt{36}

\sqrt{36} =6

BC = 6 units

As take C (11, 9) toD (4, 9).

CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}

CD = \sqrt{(7)^{2}+(0)^{2}}

CD = \sqrt{49}

\sqrt{49} =7

CD =  7 units

As take  D (4, 9) to  A (4, 3)

DA = \sqrt{(4-4)^{2}+(3-9)^{2}}

DA = \sqrt{(0)^{2}+(-6)^{2}}

DA = \sqrt{36}

\sqrt{36} =6

DA =  6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value  in the above

Area of rectangle =  7 × 6  

                             = 42 units ²

Therefore the area of a rectangle is 42 units ².

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3 years ago
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