2nd one its like one big right angle so must add to 90
So (x+9)+2x=90
Answer:
t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t = -q_1/h - sqrt((2 z)/h + ((q_1)^2)/(h^2))
Step-by-step explanation:
Solve for t:
z = (h t^2)/2 + t q_1
z = (h t^2)/2 + t q_1 is equivalent to (h t^2)/2 + t q_1 = z:
(h t^2)/2 + t q_1 = z
Divide both sides by h/2:
t^2 + (2 t q_1)/h = (2 z)/h
Add q_1^2/h^2 to both sides:
t^2 + (2 t q_1)/h + q_1^2/h^2 = (2 z)/h + q_1^2/h^2
Write the left hand side as a square:
(t + q_1/h)^2 = (2 z)/h + q_1^2/h^2
Take the square root of both sides:
t + q_1/h = sqrt((2 z)/h + q_1^2/h^2) or t + q_1/h = -sqrt((2 z)/h + q_1^2/h^2)
Subtract q_1/h from both sides:
t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t + q_1/h = -sqrt((2 z)/h + q_1^2/h^2)
Subtract q_1/h from both sides:
Answer: t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t = -q_1/h - sqrt((2 z)/h + ((q_1)^2)/(h^2))
Answer:
34.2
Step-by-step explanation:
570 x 0.06 6% is the interest
This question is not correctly written.
Complete Question
Select all equations that can represent the question: "How many groups of 4/5 are in 1?" A ?⋅1=4/5? Times 1 is equal to 4 fifths B 1⋅4/5=?1 times 4 fifths is equal to ? C 4/5÷1=?4 fifths divided by 1 is equal to ? D ?⋅4/5=1? Times 4 fifths is equal to 1 E 1÷4/5=?1 divided by 4 fifths is equal to ?
Answer:
D ?⋅4/5=1 = ? Times 4 fifths is equal to
E 1÷4/5=? = 1 divided by 4 fifths is equal to
Step-by-step explanation:
How many groups of 4/5 are in 1?
The operation used to solve this is that Division operation.
Hence, we solve it by saying:
1 ÷ 4/5 = ?
= 1× 5/4 = ?
5/4 = ?
Cross Multiply
5 = 4 × ?
? = 5/4
The equations that can represent the question: is
Option D ?⋅4/5=1 = ? Times 4 fifths is equal to
Option E 1÷4/5=? = 1 divided by 4 fifths is equal to
Answer:
Step-by-step explanation:
<u>Janet ⇒ 3 postcards ⇒ $1.05 </u>
- Cost of postcard: 1.05/3 = $0.35
<u>Rosi ⇒ 5 postcards ⇒ $1.75 </u>
- Cost of postcard: 1.75/5 = $0.35
<u>Tanya ⇒ 8 postcards ⇒ $2.80</u>
- Cost of postcard: $2.80/8 = $0.35
<u>We see in all 3 cases cost of postcard is same, the cost and numbers are proportional and the relationship is:</u>
