All categories

2 years ago

Can someone help me ?

Mathematics

1 answer:

Andreas93 [3]2 years ago

7 0

Answer:

y = -3/2x + 6

(-3/2x should look like a fraction)

You might be interested in

The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2

svetlana [45]

Answer:

The equation of tangent plane to the hyperboloid

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1$ .

Step-by-step explanation:

Given

The equation of ellipsoid

$\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1$

The equation of tangent plane at the point $\left(x_0,y_0,z_0\right)$

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1$ ( Given)

The equation of hyperboloid

$\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1$

F(x,y,z)= $\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}$

$F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}$

$(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)$

The equation of tangent plane at point $\left(x_0,y_0,z_0\right)$

$\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0$

The equation of tangent plane to the hyperboloid

$\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0$

The equation of tangent plane

$2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2$

Hence, the required equation of tangent plane to the hyperboloid

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0$

7 0

3 years ago

100 POINTS

ddd [48]

B: nine and one over two ft

8 0

1 year ago

Read 2 more answers

Start and arguement in the comments LOL

lys-0071 [83]

Answer:

Bro u need to shu.t up all ready

Step-by-step explanation:

7 0

3 years ago

Which of the following are solutions to the inequality below? Select all that apply.

AysviL [449]

Answer: j=8 and j=11

Explanation: 7(8) and 7(11) is equal to 56 and 77. 56 and 77 are both greater than 30. Therefore, the answer is j=8 and j=11.

5 0

2 years ago

Given the function f(x)=x2+2x+1, find:<br><br> f( (2a−3)/5 ) =<br><br> Show working please!

Rina8888 [55]

<h3>Given</h3>

f(x) = x² + 2x + 1

f((2a-3)/5)

<h3>Solution</h3>

It can be convenient to rewrite f(x) as a square, then do the substitution. That way, the algebra is simplified a little bit.

... f(x) = (x +1)²

... f((2a-3)/5) = ((2a-3)/5 +1)² = ((2a -3 +5)/5)²

... = (2/5(a+1))²

... f((2a-3)/5) = (4/25)(a² +2a +1)

7 0

2 years ago