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Eva8 [605]
2 years ago
9

3) Jackson ate a chocolate bar in 2 1/2 minutes. How much of the bar did he eat

Mathematics
1 answer:
nignag [31]2 years ago
3 0

Answer:

0.4 of the chocolate bar.

Step-by-step explanation:

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This is what I am supposed to do, I’m confused on what to do on 3,4, and 5. PLEASE HELP ASAP!!!!!! 30 POINTS!!!!!
max2010maxim [7]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

3

Using (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (- 3, 6)

m = \frac{6-0}{-3-0} = \frac{6}{-3} = - 2

Since the line passes through the origin (0, 0) then y- intercept is 0

y = - 2x ← equation of line

4

let (x₁, y₁ ) = (6, 0) and (x₂, y₂ ) = (0, 3)

m = \frac{3-0}{0-6} = \frac{3}{-6} = - \frac{1}{2}

note the line crosses the y- axis at (0, 3) ⇒ c = 3

y = - \frac{1}{2} x + 3 ← equation of line

5

let (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (-2, - 3)

m = \frac{-3-3}{-2-0} = \frac{-6}{-2} = 3

note the line crosses the y- axis at (0, 3) ⇒ c = 3

y = 3x + 3 ← equation of line

7 0
3 years ago
X² + 5<br> Given g(x) = 2x - 3,<br> 11,<br> x = 6<br> 2 &lt; x &lt; 6,<br> x &lt; 2<br> find g(5)
zvonat [6]

Step-by-step explanation:

uhm you know the excrotery system to the factor

5 0
3 years ago
For a company picnic, Nick ordered a box of fresh-baked gingerbread cookies and sugar cookies. The box included a total of 36 co
Mekhanik [1.2K]

Answer: 9

Step-by-step explanation:

36 ÷ 4 = 9

4 0
2 years ago
Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)​
cricket20 [7]

xe^y+4\ln y=x^2

Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).

\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}

\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x

\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

Solve for d<em>y</em>/d<em>x</em> :

e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x

\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}

If <em>y</em> ≠ 0, we can write

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}

At the point (1, 1), the derivative is

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}

4 0
3 years ago
Which is the lowest price ? per oz?
notka56 [123]
Umm i not that sure but i think its a
7 0
2 years ago
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