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tekilochka [14]
3 years ago
5

Jeanie wants to hang a circular mirror in a frame in her front wall. Determine the area of the largest mirror Jeanie can han if

the frame has a circumference of 56 inches.
Mathematics
1 answer:
AnnyKZ [126]3 years ago
3 0
56=2(pi)(r)
r=8.9127
pi(8.9127)^2=249.56cm^2
≈245cm^2 (3s.f.)
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padilas [110]

y=\sqrt x\,e^{x^2}(x^2+5)^{12}=x^{1/2}e^{x^2}(x^2+5)^{1/2}

Take the logarithm of both sides and expand the right hand side:

\ln y=\ln\left(x^{1/2}e^{x^2}(x^2+5)^{1/2}\right)

\ln y=\ln x^{1/2}+\ln e^{x^2}+\ln(x^2+5)^{12}

\ln y=\dfrac12\ln x+x^2\ln e+12\ln(x^2+5)

\ln y=\dfrac12\ln x+x^2+12\ln(x^2+5)

Now take the derivative of both sides with respect to x:

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\dfrac{\mathrm dy}{\mathrm dx}=\left(\dfrac1{2x}+2x+\dfrac{24x}{x^2+5}\right)y

\dfrac{\mathrm dy}{\mathrm dx}=\left(\dfrac1{2x}+2x+\dfrac{24x}{x^2+5}\right)\sqrt x\,e^{x^2}(x^2+5)^{12}

I'd stop there, but you could condense the right side a bit to get

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4x^4+21x^2+48x+5}{2x(x^2+5)}\sqrt x\,e^{x^2}(x^2+5)^{12}

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4x^4+21x^2+48x+5}{2\sqrt x}e^{x^2}(x^2+5)^{11}

8 0
4 years ago
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