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3 years ago

What is climate and what are the two main factors that affect climate?

Chemistry

1 answer:

Illusion [34]3 years ago

5 0

Answer:

climate:the weather conditions prevailing in an area in general or over a long period.

2 main factors: temperature and precipitation

Explanation:

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When working with food, personal items such as a cell phone should be

vlabodo [156]

Answer:

prohibited because of germs that are on your phone.

Explanation:

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3 years ago

Read 2 more answers

Solid lead(11) carbonate reacts with a dilute solution of

vichka [17]

Answer:

PbCO₃ + 2HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

Explanation:

From the question given above:

Solid lead (II) carbonate reacts with a dilute solution of nitric acid (HNO₃) to give a solution of lead (II) nitrate,

carbon dioxide and water.

The above can be represented in the equation form as follow:

PbCO₃ + HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

Finally, we shall balance the equation as follow:

PbCO₃ + HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HNO₃ as shown below:

PbCO₃ + 2HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

Now, the equation is balanced.

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3 years ago

I GIVE BRAINLIEST TO WHO EVER GETS IT RIGHT!

Gala2k [10]

Answer: B. Bohr and D. Rutherford

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3 years ago

If you are measuring something with a graduated cylinder, what are you measuring?

JulijaS [17]

With a graduated cylinder, you are most likely measuring mL (milliliters) or volume of a liquid, or the mass of a liquid.

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3 years ago

Calculate the pH and fraction of dissociation ( α ) for each of the acetic acid ( CH 3 COOH , p K a = 4.756 ) solutions. A 0.002

marysya [2.9K]

Answer:

The degree of dissociation of acetic acid is 0.08448.

The pH of the solution is 3.72.

Explanation:

The $pK_a=4.756$

The value of the dissociation constant = $K_a$

$pK_a=-\log[K_a]$

$K_a=10^{-4.756}=1.754\times 10^{-5}$

Initial concentration of the acetic acid = [HAc] =c = 0.00225

Degree of dissociation = α

$HAc\rightleftharpoons H^++Ac^-$

Initially

At equilibrium ;

(c-cα) cα cα

The expression of dissociation constant is given as:

$K_a=\frac{[H^+][Ac^-]}{[HAc]}$

$1.754\times 10^{-5}=\frac{c\times \alpha \times c\times \alpha}{(c-c\alpha)}$

$1.754\times 10^{-5}=\frac{c\alpha ^2}{(1-\alpha)}$

$1.754\times 10^{-5}=\frac{0.00225 \alpha ^2}{(1-\alpha)}$

Solving for α:

α = 0.08448

The degree of dissociation of acetic acid is 0.08448.

$[H^+]=c\alpha = 0.00225M\times 0.08448=0.0001901 M$

The pH of the solution ;

$pH=-\log[H^+]$

$=-\log[0.0001901 M]=3.72$

3 0

4 years ago