Answer:
PbCO₃ + 2HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O
Explanation:
From the question given above:
Solid lead (II) carbonate reacts with a dilute solution of nitric acid (HNO₃) to give a solution of lead (II) nitrate,
carbon dioxide and water.
The above can be represented in the equation form as follow:
PbCO₃ + HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O
Finally, we shall balance the equation as follow:
PbCO₃ + HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O
There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HNO₃ as shown below:
PbCO₃ + 2HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O
Now, the equation is balanced.
