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2 years ago

What is the equation of the line that passes through the point (- 4, 1) and has slope of - 3/4 ?

Mathematics

1 answer:

Katarina [22]2 years ago

4 0

Y-1=-3/4(x+4)
y-1=-3/4x-3
Add 1 to each side
slope intercept- y=-3/4x-2
Point slope intercept form- y-1=-3/4x-3

You might be interested in

A factory produces 90 packages of mixed nuts in 1 min. A quality control manager selected 10 of these 90 packages at random and

valentina_108 [34]

Answer:

34

explanation:

First of all, put the numbers in order

30, 31, 31, 32, 33, 35, 35, 35, 36, 36

Then, find the middle number.
In this case, there is an even amount of numbers so, we have to pick the 2 middle numbers which is 33 and 35.

Now all you have to do is add these two numbers together then divide by 2 which will give you 34.

or, in simpler questions like this one, you can just say 34 as you know it is between 33 and 35.

In other questions, it might have and odd amount of numbers, for example:

3, 3, 5, 8, 10

so all you would do here is pick the middle number which would be 5. (it has 2 numbers on each side of it)

7 0

2 years ago

If sin phi sin theta = 0.2 and sin phi cos theta = -0.3 and sin phi > 0 what is theta ? Repeat for sin phi < 0.

Rina8888 [55]

Answer:

θ = -33.69°

Step-by-step explanation:

For Φ>0 and Φ<0 (in general Φ≠nπ where n is an integer), sin(Φ) ≠ 0

Dividing both equations:

$\frac{sin(\phi) sin(\theta)}{sin(\phi)cos(\theta)} = tan(\theta) = 0.2/(-0.3)=-2/3\\$

Therefore:

arctan(θ) = -2/3

θ = -33.69°

The answer does not depend on the sign of Φ, in fact we just need that the sine does not become zero, which occurs when Φ is equal to an integer times π (radians) or 180 (degrees)

Have a nice day!

3 0

3 years ago

6. An ostrich cannot fly, but it is able to run fast. Suppose an ostrich runs east for 7.95 s and then runs 161 m south, so that

Liula [17]

Answer:

159 m

Step-by-step explanation:

From the information given:

It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.

Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.

Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.

We are to find, the magnitude of the ostrich's eastward component.

i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.

Using the Pythagoras rule:

ES² = OE² + OS²

226² = OE² + 161²

226² - 161² = OE²

OE² = 226² - 161²

OE² = 51076 - 25921

OE² = 25155

$OE = \sqrt{25155}$

OE = 158.60 m

OE ≅ 159 m

Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.

4 0

3 years ago

The zoo charges the Garcia family an admission fee of $5.25 per person

Anuta_ua [19.1K]

Answer:

could you please provide more context? the questions is missing key information

4 0

3 years ago

7.3033 to the nearest foot

pychu [463]

Answer:

7 feet

Step-by-step explanation:

If it is under .5 keep the whole number the same, if it is .5 or more round up. This is .3 so it is 7.

7 0

3 years ago

Read 2 more answers