What are the volumes and surface areas of these figures?

Mathematics

1 answer:

REY [17]2 years ago

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Answer:

please don't put a picture of your mother on this site

Step-by-step explanation:we are professional here and i don't want to have to call HR on you.

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2 years ago

Three perfect cube blocks of different volumes were stacked on top of each other. The top block was 64 cubic centimeters, the mi

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We know that

[volume of a cube]=b³---------> b=∛Volume
b------> is the side length of a cube

The top block was 64 cm³------> b1=∛64-------> b1=4 cm
The middle block was 125 cm³------> b2=∛125------> b2=5 cm
The biggest block was 729 cm³------> b3=√729------> b3=9 cm

[the stack of blocks tall]=b1+b2+b3-------> 4+5+9-----> 18 cm

the answer is
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3 years ago

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check the picture below.

bearing in mind that there are 60 minutes in 1 degree, then 16°18' will be 16.3° and likewise 48°51' will be 48.85° if we convert those to degrees only.

$\bf y=\cfrac{200}{tan(48.85^o)}~\hspace{10em}x=\cfrac{200}{tan(16.3^o)}-y \\\\\\ x=\cfrac{200}{tan(16.3^o)}-\cfrac{200}{tan(48.85^o)}\implies x\approx 683.95 - 174.78\implies x\approx 509.17$

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katrin2010 [14]

$\dfrac{n^2+3n+2}{n^2+6n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n^2+2n+n+2}{n^2+4n+2n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n(n+2)+1(n+2)}{n(n+4)+2(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{(n+2)(n+1)}{(n+2)(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{n+1}{n+4}-\dfrac{2n}{n+4}=\dfrac{n+1-2n}{n+4}=\dfrac{1-n}{n+4}$

$Answer:\ \boxed{B.\ \dfrac{1-n}{n+4}}$

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