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irinina [24]
3 years ago
9

Does the equation 3(2x−1)+5=6(x+1) have one, none, or an infinite amount of solutions?

Mathematics
2 answers:
EleoNora [17]3 years ago
8 0

Answer: No solutions

Step-by-step explanation: If you solve the problem all the way, you get 0 = 4 which is not valid so there is simply no solution

prisoha [69]3 years ago
7 0

Answer:

no solution

Step-by-step explanation:

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Please help thank u
ad-work [718]

Answer:

12

Step-by-step explanation:

5 0
3 years ago
I need help! Answer as fast as you can. Marking brainlyiest
grandymaker [24]

Answer:

A

Step-by-step explanation:

We can break down what each term represents in the equation

60 is the constant. This is the base price that is paid regardless of workers and hours needed

Then there is 12nh. 12 represents the cost per hour for one worker. If the job takes only one hour, then it is 12 dollars per worker. Similarly, if the job only takes one person, then it is 12 dollars for each hour.

The most accurate answer is A

8 0
3 years ago
X^2 - 4x + 3 how do I factor the expression completely
Ipatiy [6.2K]
Bx must be the sum of the numbers in the bracket and c must be the product. So we need to choose 2 numbers that multiply to make 3 and add to make -4.

A negative x negative = positive so
-3*-1=3
-3-1=-4

Therefore:
(x-3)(x-1)
8 0
3 years ago
Read 2 more answers
ANSWER TO BE NAMED BRAINLIEST GET A THANK YOU A FOLLOW AND 25 PPTS
Svet_ta [14]

Answer:

192 cm^3

Step-by-step explanation:

Volume for rectangular prism is V=l*w*h

V=8*4*6=32*6=192

So volume is 192 cm^3

8 0
3 years ago
n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,
Nitella [24]

Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

A = Pe^{rt}

Where,

P = initial population,

r = growth rate per period,

t = number of periods,

Given,

The population in 2000, P = 2,400,

Growth rate per year = 1.68% = 0.0168,

Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

A=2400 e^{0.0168\times 20}

=2400 e^{0.336}

= 3358.4136

\approx 3358

6 0
3 years ago
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