Please help and thank you
2 answers:
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The first , second, and fourth options if you are on edge.
1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula to find the distance from point
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: .
Answer:
All solutions
Step-by-step explanation:
When solving by substitution, we will first set one equation equal to a variable, and then plug that value into the second equation as the variable. Here is what I mean;
x - 2y = 1
3x - 6y = 3
-
x = 1 + 2y
3x - 6y = 3
-
3(1 + 2y) - 6y = 3
3 + 6y - 6y = 3
3 = 3
[] Oh no! This doesn't work well. Let's graph it and see what is happening;
-> See attached
-> I have made the lines very thick so you can see the overlap, they are the same size in reality
The answer is all solutions because the graphs are exactly the same.
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.
- Heather
