Taking into consideration that the interest is compound (yearly)
the amount of money gather through the years can be calculated by
A = P (1+r)^(t)
6000 = 5000 (1.03)^t
t = ln(6000/5000)/ln(1.03) = 6.16 ≈ 7
c. 7 years
Answer:
125 = 5 * 5 * 5 = 5^3
Step-by-step explanation:
125 is equal to 5 times 5 times 5, and a power is a way to write repeated multiplication, just by saying what number it is and the putting a ^ sign and then saying how many times there is that number. There is 5 three times, so the power is 5^3.
Answer:
Option A is correct.
Step-by-step explanation:
As we see the graph, we can say that the correct statement is :
A.)All repairs requiring 1 hour or less have the same labor cost. We can see that the coat from 0 hours to 1 hour is $50. So, the number of hours falling in this range has the same repairing cost.
B.) Labor costs the same no matter how many hours are used for a repair. This is wrong as the graph is increasing after 1 hour.
C.) Labor costs for a repair are more expensive as the number of hours increases. This is wrong as the hours are increasing from 0.25 to 0.5 then to 0.75 but they all have the same cost.
D.)There is no cost of labor for a repair requiring less than 1 hour. This is also wrong. The cost is $50.
Answer: No.
Step-by-step explanation: g should also be factored out. 10g(a - 3z).
