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velikii [3]
3 years ago
5

Solve 2x>8 or 2x<4 Please hurry

Mathematics
2 answers:
horsena [70]3 years ago
7 0

Answer:

x = 5

Step-by-step explanation:

2 * 5 = 10 which is greater than 8

10 > 8

tino4ka555 [31]3 years ago
6 0

Answer: x>4 and then x<2

Step-by-step explanation: divide by 2 on both sides

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A business owner has just paid $6000 for a computer. It depreciates at a rate of 22% per year. How much will it be worth in 5 ye
katovenus [111]

Answer:

It will be worth $1732.30.

Step-by-step explanation:

After 1 year : 6000 x .78 = 4680

2 yr - 4680 x .78 = 3650.4

3 yr - 3650.4 x .78 = 2847.312

4 yr - 2847.312 x .78 = 2220.90336

5 yr - 2220.90336 x .78 = 1732.304621

1732.30

I think this is what it was asking

7 0
4 years ago
1. cot x sec4x = cot x + 2 tan x + tan3x
Mars2501 [29]
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
    cot(x)sec⁴(x)            cot(x)sec⁴(x)
                   0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
                   0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
                   0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
                   0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
                   0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
                   0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
                   0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
                   0 = cos⁴(x)(1 + tan²(x))²
                   0 = cos⁴(x)        or         0 = (1 + tan²(x))²
                ⁴√0 = ⁴√cos⁴(x)      or      √0 = (√1 + tan²(x))²
                   0 = cos(x)         or         0 = 1 + tan²(x)
         cos⁻¹(0) = cos⁻¹(cos(x))    or   -1 = tan²(x)
                 90 = x           or            √-1 = √tan²(x)
                                                         i = tan(x)
                                                      (No Solution)

2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
              sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
   sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
                               sin²(x) - cos²(x) = sin²(x) - cos²(x)
                                         + cos²(x)              + cos²(x)
                                             sin²(x) = sin²(x)
                                           - sin²(x)  - sin²(x)
                                                     0 = 0

3. 1 + sec²(x)sin²(x) = sec²(x)
           sec²(x)             sec²(x)
      cos²(x) + sin²(x) = 1
                    cos²(x) = 1 - sin²(x)
                  √cos²(x) = √(1 - sin²(x))
                     cos(x) = √(1 - sin²(x))
               cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
                                 x = 0

4. -tan²(x) + sec²(x) = 1
               -1               -1
      tan²(x) - sec²(x) = -1
                    tan²(x) = -1 + sec²
                  √tan²(x) = √(-1 + sec²(x))
                     tan(x) = √(-1 + sec²(x))
            tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
                             x = 0
5 0
3 years ago
explain why there is never a single correct answer to a question that asks you to estimate some quantity
motikmotik
Because others would estimate it differently. 
7 0
4 years ago
What is 2/7 ÷ 4/5 ? Plz help
dem82 [27]

Answer:

5/14

Step-by-step explanation:

4 0
3 years ago
How do I solve this (trigonometry)
kow [346]

Answer:

3/5

Step-by-step explanation:

the sin of an acute angle in a right triangle is the ratio of the opposite side to the hypotenuse

24/40=3/5

7 0
3 years ago
Read 2 more answers
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