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denis23 [38]
3 years ago
7

Find the missing side of this right triangle. Х 6 10

Mathematics
1 answer:
Alik [6]3 years ago
8 0
X² = 10² + 6²
X² = 100 + 36
X² = 136
X = √136
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Is 60n + 12 equal to 12(5n + 1)
hram777 [196]

Answer: no

Step-by-step explanation:

5 0
3 years ago
1.the graph of y = x² is moved five units upward
KonstantinChe [14]

Answer:

I guess that we want to find the equation for each case.

First, let's define the translations:

Horizontal translation.

For a function f(x), an horizontal translation of N units is written as:

g(x) = f(x + N)

if N > 0, the translation is to the left

if N < 0, the translation is to the right.

Vertical translation:

For a function f(x), a vertical translation of N units is written as:

g(x) = f(x) + N

if N > 0, the translation is upwards

if N < 0, the translation is downwards.

Now that we know these, we can find the equations for each case:

1. the graph of y = x² is moved five units upward

the graph is given by a vertical translation of 5 units upward.

y = x^2 + 5

2 the graph of y = 5x² is moved six units to the left

this is:

y = 5*(x + 6)^2

3: the graph of y = -2x² is moved seven units downward

this is:

y = -2x^2 - 7

4: the graph of y = -x² is moved two units to the left and four units downward

now we have two translations, first 4 units to the left and then 4 units downwards, this gives:

y = -(x + 4)^2 - 4

5: the graph of y = -3x² is moved two units to the right

Remember that to move the graph to the right, we need to have N negative, then:

y = -3(x - 2)^2

8 0
2 years ago
How many 4 digit numbers consisting of only the digits 2,4,6 and 8 are divisible by 4
Blababa [14]

Answer:

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  • repeated digits: 128

Step-by-step explanation:

In order for a number to be divisible by 4, its last two digits must be divisible by 4. This will be the case if either of these conditions holds:

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We must count the ways these conditions can be met with the given digits.

__

Since we only have even numbers to work with, the ones digit must be an even multiple of 2: 4 or 8. (The tens digit cannot be odd.) The digits 4 and 8 comprise half of the available digits, so half of all possible numbers made from these digits will be divisible by 4.

<h3>digits used once</h3>

If the numbers must use each digit exactly once, there will be 4! = 24 of them. 24/2 = 12 of these 4-digit numbers will be divisible by 4.

<h3>repeated digits</h3>

Each of the four digits can have any of four values, so there will be 4^4 = 256 possible 4-digit numbers. Of these, 256/2 = 128 will be divisible by 4.

7 0
2 years ago
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arsen [322]

Answer:

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2 years ago
Y= x + 2<br> y= x + 6<br> How many solutions
Alona [7]

there \: is \: not \: any \: solutin \: for \: it \\ x + 2 = x + 6 \\ 2 = 6 \: is \: wrong

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