Answer:
576 Calories a 16 kilogram dog needs each day.
Step-by-step explanation:
The approximate number of Calories, C , that an animal needs each day is given by
,
where m is the animal's mass in kilograms.
now we find the number of Calories that a 16 kilogram dog needs each day.
we are given with m=16
So plug in 16 for m in the given equation

576 Calories a 16 kilogram dog needs each day.
Use the formula d=sqrt[(x_2-x_1)^2+(y_2-y_1)^2]
sqrt=squareroot
Answers d=10
2/3 (0.666) quantities fills one dispenser.
Step-by-step explanation:
Step 1; It is given that 2 1/3 amount of some liquid fills up 3 1/2 dispensers. First, we must convert the mixed fractions into improper fractions. To do that we multiply the number with the denominator and add with it the numerator whereas the denominator remains the same. To convert the fraction
2 1/3 we multiply the 2 with the 3 and add it with 1 while denominator remains 3, so 2 1/3 becomes 7/3. Similarly the fraction 3 1/2 converts into 7/2.
Step 2; So we have 7/3 quantities of liquid fills 7/2 dispensers. We multiply both sides by 2/7 so that the right side of the equation becomes 1 and the left side of the equation indicates the amount of liquid in 1 dispenser.
7/3 * 2/7 = 7/2 * 2/7 , 14/21 = 1 dispenser. So 14/21 = 2/3. So 2/3 or 0.666 quantity of liquid fills one dispenser.
For a function of
, the average rate of change can be found as follows:

So, we only need two points to compute this value. So, in this problem we have a table with several points, but the problem establishes that the ARC we need to find is the one between two points, that is, when x=3 and x=4. In this problem,
is the function, so:
