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tiny-mole [99]
3 years ago
10

The larger square garden at Volterra Hall has sides twice as long as the smaller square garden. Together the gardens cover 18,00

0 square feet. Find the dimensions of each garden.

Mathematics
1 answer:
boyakko [2]3 years ago
6 0
We will call:
G_{1}: The larger square garden.
G_{2}: The smaller square garden.

Given that both of then have square areas, then:
A_{G1} =    L_{G1}^{2}
A_{G2} = L_{G2}^{2}

Being L_{G1} the side of the larger garden and L_{G2} the side of the smaller garden as shown in the figure.

<span>The larger square garden at Volterra Hall has sides twice as long as the smaller square garden, thus:

</span>L_{G1} = 2L_{G2}

<span>Together the gardens cover 18,000 square feet, so:
</span>A_{G1} + A_{G2} = L_{G1}^{2} + L_{G2}^{2} = 18000

Then:
(2L_{G2})^{2} + L_{G2}^{2} = 18000
4L_{G2}^{2} + L_{G2}^{2} = 18000
5L_{G2}^{2} = 18000
L_{G2}^{2} = 3600
L_{G2} =  \sqrt{3600}
L_{G2} =  60
L_{G1} = 2L_{G2} = 2(60) = 120

Therefore:
Each side of the larger square garden is 120 ft and each side of the smaller one is 60 ft each. These are the dimensions.

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