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3 years ago

PLZ HELP 16 POINTS

Physics

2 answers:

levacccp [35]3 years ago

3 0

Answer:

It is a product formed.

Explanation:

when carbon di oxide and water react with help of sun light glucose and O2 becomes product.

FrozenT [24]3 years ago

3 0

Answer:

it is converted with light energy.

Explanation:

i got a 100 on my test

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A roller-coaster car moves 172 ft horizontally and then rises 115 ft at an angle of 31.0° above the horizontal. it next travels

lianna [129]

172 + 115 cos 31 +115 cos 48 horizontally

115 sin 31 - 115 sin 48 vertically

possibly need some drawing

4 0

3 years ago

A horizontal circular platform (m = 119.1 kg, r = 3.23m) rotates about a frictionless vertical axle. A student (m = 54.3kg) walk

Murrr4er [49]

Answer:

$\omega_2=5.1rad/s$

Explanation:

Since there is no friction angular momentum is conserved. The formula for angular momentum thet will be useful in this case is $L=I\omega$ . If we call 1 the situation when the student is at the rim and 2 the situation when the student is at $r_2=1.39m$ from the center, then we have:

$L_1=L_2$

Or:

$I_1\omega_1=I_2\omega_2$

And we want to calculate:

$\omega_2=\frac{I_1\omega_1}{I_2}$

The total moment of inertia will be the sum of the moment of intertia of the disk of mass $m_D=119.1 kg$ and radius $r_D=3.23m$ , which is $I_D=\frac{m_Dr_D^2}{2}$ , and the moment of intertia of the student of mass $m_S=54.3kg$ at position $r$ (which will be $r_1=r=3.23m$ or $r_2=1.39m$ ) will be $I_{S}=m_Sr_S^2$ , so we will have:

$\omega_2=\frac{(I_D+I_{S1})\omega_1}{(I_D+I_{S2})}$

or:

$\omega_2=\frac{(\frac{m_Dr_D^2}{2}+m_Sr_{S1}^2)\omega_1}{(\frac{m_Dr_D^2}{2}+m_Sr_{S2}^2)}$

which for our values is:

$\omega_2=\frac{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(3.23m)^2)(3.1rad/s)}{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(1.39m)^2)}=5.1rad/s$

6 0

3 years ago

A 1500 kg car traveling to the north is slowed down uniformly from initial velocity of 20 m/s by a 6000 N braking force acting o

aev [14]

Answer:

12 m/s

Explanation:

Given data

Mass m= 1500kg

intitial velocity u= 20m/s

force F= 6000N

time t= 2 seconds

Required

The final velocity v

From

Ft= mΔv

Ft= m(u-v)

substitute

6000*2= 1500(20-v)

solve for v

12000= 30000- 1500v

collect like terms

12000-30000= -1500v

-18000= -1500v

divide both sides by -1500v

v= 18000/1500

v=12 m/s

Hence the velccity is 12 m/s

3 0

3 years ago

State laws of magnetism

kykrilka [37]

Explanation:

A basic law of magnetism is that unlike poles attract each other. Two bar magnets can illustrate this. ... A pole of the second is brought, in turn, near each of the two ends of the hanging magnet.

Second Law of Magnetism

The force is in direct proportion to the product of the forces of the pole. The force exists in inverse proportion to the square of the middle distance between the poles. The force is dependent on the specific medium in which the magnets are placed.

4 0

3 years ago

Place these features in order from smallest to largest: mountain system, mountain range, mountain belt, mountain.

abruzzese [7]

Answer:

Mountain, Mountain range, Mountain system, Mountain belt.

4 0

3 years ago