Using KE = 1/2mv^2
m = mass (80kg)
v = velocity (?)
KE = kinetic energy (2500J)
2500/((1/2) x (80)) = v^2
Square root the answer to get: 7.91 m/s
Yes I’m going home I was finna was your birthday and I got to get my kids ready
Answer:
Answer: C
explanation:
They could be same or different
ie:
|-5|,|-5| = 5,5
|-5|,|5| = 5,5
The equation is garbled and the question is missing.
I found this equation for the same statement:
S = - 2.7t ^2 + 30t + 6.5
And one question is: after how many seconds is the ball 12 feet above the moon's surface?
Given that S is the height of the ball, you just have to replace S with 12 and solve for t.
=> 12 = - 2.7 t^2 + 30t + 6.5
=> 2.7t^2 - 30t - 6.5 + 12 = 0
=> 2.7t^2 - 30t + 5.5 = 0
Now you can use the quadratic equation fo find t:
t = { 30 +/- √ [30^2) - 4(2.7)(5.5)] } / (2*2.7)
=> t = 0.186s and t = 10.925 s
Answer: after 0.186 s the ball is at 12 feet over the surface, and again 10.925 s
