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pychu [463]
3 years ago
10

A unit of time sometimes used in microscopic physics is the "shake". One shake equals 10−8 s.

Physics
1 answer:
Lady_Fox [76]3 years ago
3 0

Answer:

(a) There are 3.17 times more shakes in a second than seconds in a year.

(b) Humans have existed for 9067.72 universe seconds.

Explanation:

(a) First we calcule how many seconds are in a year. One year have 365 days, one day has 24 hours, one hour has 60 minutes and one minute has 60 seconds, so:

60s*60*24*365=3.1536*10^7s

Now, we calculate how many shakes are in a second:

1s*\frac{1shake}{10^{-8}s}=10^8shakes

Finally, we calculate how many more shakes in a second are there than seconds in a year:

\frac{10^8s}{3.1536*10^7s}=3.17

(b) Using a simple rule of three we can calculate  how many "universe seconds" have humans existed, recall that 1 day has 86400 seconds:

1010 years--------->86400s

106 years----------> x seconds

x=\frac{106y*86400s}{1010y}=9067.72s

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If 30.45 grams of water is to be heated up 3.3 degrees to make baby
KengaRu [80]

Answer:

A. 420 J

Explanation:

Given the following data;

Mass = 30.45 g

Specific heat capacity = 4.18 J/g °C.

Temperature = 3.3°C

To find the quantity of heat;

Heat capacity is given by the formula;

Q = mct

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

t represents the temperature.

Substituting into the equation, we have;

Q = 30.45 * 4.18 * 3.3

Q = 420.03 ≈ 420 Joules

8 0
3 years ago
The total amount of force exerted on an object is called
ziro4ka [17]

Answer:

net force

Explanation:

net force is the total amount of force exerted on an object.

7 0
3 years ago
As speed increases, how does the potential, kinetic, and total energy levels change?
Anastaziya [24]
Potential equals kenecric at the bottom so potential would also increas
4 0
3 years ago
a projectile is fired in such away that its horizontal range is equal to three times its naximum height.what is the angle of pro
finlep [7]

Answer:

\theta=53.13^o

Explanation:

<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

V_x=V_{ox}=V_ocos\theta

V_y=V_{oy}-gt=V_osin\theta-gt

x=V_{ox}t

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

\displaystyle x_{max}=\frac{2V_{ox}V_{oy}}{g}

\displaystyle y_{max}=\frac{V_{oy}^2}{2g}

The projectile is fired in such a way that its horizontal range is equal to three times its maximum height. We need to find the angle \theta at which the object should be launched. The range is the maximum horizontal distance reached by the projectile, so we establish the base condition:

x_{max}=3y_{max}

\displaystyle \frac{2V_{ox}V_{oy}}{g}=3\frac{V_{oy}^2}{2g}

Using the formulas for V_{ox}, V_{oy}:

\displaystyle \frac{2V_{o}cos\theta V_{o}sin\theta}{g}=3\frac{V_{o}^2sin^2\theta}{2g}

Simplifying

4cos\theta sin\theta=3sin^2\theta

Dividing by sin\theta

4cos\theta=3sin\theta

Rearranging

tan\theta=\frac{4}{3}

\theta=arctan\frac{4}{3}

\theta=53.13^o

4 0
3 years ago
Jazz is a 172 lb athlete who exercised at 7.6 METs. At this workload, what is his energy expenditure in kcals/min.? Round to the
dezoksy [38]

Answer:

Energy expenditure in K cals/min = 10 K cals /min (approximately)

Explanation:

As we know

Energy expenditure in Kcal/min=  METs x 3.5 x Body weight (kg) / 200

Given is METs=7.6

Weight of Jazz= 172lb=78.02kg

putting the values in formula,

Energy expenditure in K cals/min=  7.6 x 3.5 x 78.02 / 200

                                                       =10.38 K cals /min

                                                       =10 K cals /min (approximately)

Therefore, Energy expenditure in K cals/min by Jazz will be approximately 10 K cals /min

8 0
3 years ago
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