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lorasvet [3.4K]

3 years ago

15

for every touchdown scored by the Timberwolves the mascot does 3 back flips and the cheerleaders set off 6 confetti connons how

many touchdowns did the Timberwolves score if the cheerleaders set of 6 confetti cannons

1 answer:

miskamm [114]3 years ago

5 0

Answer:

1

Step-by-step explanation:

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What is 5 1/4 - 3 3/8<br> In a fraction

Maksim231197 [3]

First, turn the fractions into mixed numbers.

21/4 - 27/8

Then. make the denominators the same.

4 * 2 = 8

21 * 2 = 42

42/8 - 27/8

42 - 27 = 15

15/8

15/8 = 1 7/8

3 0

4 years ago

Write each of the below number in an descending order.<br> 8.09 7.36 8.1 7.32 8.13

andreev551 [17]

Answer:

8.13 8.1 8.09 7.36 7.32

is the order

8 0

2 years ago

1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.

iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is $53.13\°$

Part 2) The surface area of the pyramid is $288\ cm^{2}$

Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

In the right triangle o the figure

The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

$sin(x)=\frac{16}{20}$

$x=arcsin(\frac{16}{20})=53.13\°$

Bob's mistake was to have used the cosine instead of the sine

Part 2) we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

$SA=b^{2}+4[\frac{1}{2}(b)(h)]$

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

$h=b/2$ -------> by an 45° angle

so

$b=2h$

$sin(45\°)=\frac{h}{6\sqrt{2}}$

$h=6\sqrt{2}(sin(45\°))=6\ cm$

Find the value of b

$b=2(6)=12\ cm$

Find the surface area

$SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}$

3 0

4 years ago

Angle and Kenny play online video games Angle buys 2software package and 3 months of game play Kenny buys 2 software packages an

Vsevolod [243]

Answer:

I got 29

Step-by-step explanation:

5 0

3 years ago

The human eye blinks about 6.25x10 to the 6th power times each year. A seal blinks about 1.01x10 to the 3rd power times per year

OLEGan [10]

A human blinks 6,250,000 times a year.
A seal blinks 1,010 times a year.

8 0

3 years ago