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laiz [17]
3 years ago
6

If a vertical line is dropped from the x-axis to the point (12, –9) in the diagram below, what is the value of sec?

Mathematics
2 answers:
dem82 [27]3 years ago
5 0

Answer:

Value of \sec \theta = \frac{5}{4}

Step-by-step explanation:

Given: A vertical line is dropped from the x-axis to the point (12, -9) as shown in the diagram below;

To find the value of \sec \theta.

By definition of secants;

\sec \theta = \frac{1}{\cos \theta}

Now, first find the cosine of angle \theta

As the point (12 , -9) lies in the IV quadrant , where \cos \theta > 0

Consider a right angle triangle;

here, Adjacent side = 12 units and Opposite side = -9 units

Using Pythagoras theorem;

(Hypotenuse side)^2= (12)^2 + (-9)^2 = 144 + 81 = 225

or

Hypotenuse = \sqrt{225} =15 units

Cosine ratio is defined as in a right angle triangle, the ratio of adjacent side to hypotenuse side.

\cos \theta = \frac{Adjacent side}{Hypotenuse side}

then;

\cos \theta = \frac{12}{15} = \frac{4}{5}

and

\sec \theta = \frac{1}{\cos \theta}= \frac{1}{\frac{4}{5}} = \frac{5}{4}

therefore, the value of \sec \theta is, \frac{5}{4}

Debora [2.8K]3 years ago
3 0

Answer:

B

Step-by-step explanation:

took the test

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Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

  • The lower bound is of 0.484.
  • The upper bound is of 0.7292.
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In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

Supposing that it increases on 37 out of 61 days:

n = 61, \pi = \frac{37}{61} = 0.6066

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292

The ​95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.

The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

A similar problem is given at brainly.com/question/16807970

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The explanation for this would because because the two base angles of an isosceles triangle are equal so since the both equal to 40 degrees, in total would be 80 degrees.

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What is LCM of 2 4 8​
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Answer:

the LCM would be 8 based on the following set of multiples: Multiples of 2: 2, 4, 6, 8, 10, 12, 14, ... Multiples of 8: 8, 16, 24, 32, 40, 48, 56, ...

Step-by-step explanation:

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3. The Luxor hotel, in Las Vegas, is a square pyramid with lateral faces consisting of black, glassed mirrored panes. The buildi
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Jeff received 280$ from his mother

Such questions are the simplest as it needs you to just write the conditions accordingly which then simplifies and provides you the answer.

This question can be solved using two tricks which are shown below:-

Trick  1 :

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1/4 – 410 (used for 8th and 9th days)

(3/4)/7 ——- (1/4 – 10)/2

(3/4) x (2/7) = 3/14 ——- (1/4 – 10)

1/4 – 3/14 = (7 – 6)/28 = 1/28 ——- 10

28/28 ——- 10 x 28 =$ 280

Trick 2 :

7 days ——- 3/4

1 day ——- 3/28

2 days ——- 6/28

6/28 ——- (1/4 – 10) = 7/28 – 410

1/28 ——- 10

28/28 ——- 10 x 28 = $280

Thus Jeff received 280$ from his mother.

Learn more about simple math here :

brainly.com/question/23678

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