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3 years ago

Log16 (x squared - 3x + 12) = 1

Mathematics

1 answer:

vovangra [49]3 years ago

3 0

Log_(16)(x^2 - 3x + 12) = 1
x^2 - 3x +12 = 16
x^2 - 3x - 4 = 0
x = [3 ± √(3^2 - 4(1)(-4))]/[2(1)] = [3 ± 5]/2 = 4, -1

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Answer

x - 1 + 6x^2

Step-by-step explanation:

Write al the sides together: 2x + 5 + x^2 - 6 + 4x^2 + 2x + x^2 - 3x

Then organize the terms: 2x + 2x - 3x + 5 - 6 + x^2 + x^2 + 4x^2

Simplify: 2x + 2x - 3x + 5 - 6 + x^2 + x^2 + 4x^2

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3 years ago

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Answer:

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Step-by-step explanation:

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Also, x = 9. To find x, we'll have:

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