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2 years ago

10

A coach spends a total of $435 to buy a uniform and a soccer ball for each of the 15 players on the team. The cost of each socce

r ball is 8$
Which equation can be used to find the cost of each uniform?

1 answer:

ale4655 [162]2 years ago

3 0

15 players times the uniforms(x) and the cost of the ball equals the total spent 15(x+8)=435

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An article includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberr

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Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean compression strength from the extra carbonation of strawberry drink and μ2 be the mean compression strength from the extra carbonation of cola.

The random variable is μ1 - μ2 = difference in the mean compression strength from the extra carbonation of strawberry drink and the mean compression strength from the extra carbonation of cola.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 < μ2 H1 : μ1 - μ2 < 0

This is a left tailed test.

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 530

x2 = 553

s1 = 23

s2 = 16

n1 = 10

n2 = 10

t = (530 - 533)/√(23²/10 + 16²/10)

t = - 2.6

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [23²/10 + 16²/10]²/[(1/10 - 1)(23²/10)² + (1/10 - 1)(16²/10)²] = 6162.25/383.752

df = 16

We would determine the probability value from the t test calculator. It becomes

p value = 0.0097

Since alpha, 0.05 > than the p value, 0.0097, then we would reject the null hypothesis. Therefore, at 5% significance level, the data suggests that the extra carbonation of cola results in a higher average compression strength.

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3 years ago

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Step-by-step explanation:

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2 years ago

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Answer:

To earn $10 in 1st month, the principal must be $4,000.

No, the poster cannot claim that "Open an account of $2 comma 500 and earn at least $10 interest in 1 month!".

Step-by-step explanation:

We have been given that a bank manager wants to encourage new customers to open accounts with principals of at least $2,500. He decides to make a poster advertising a simple interest rate of 3%. We are asked to find the principal to advertise that one can earn $10 the first month.

We will use simple interest formula to solve our given problem.

$I=Prt$ , where,

I = Amount of interest,

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r = Annual interest rate in decimal form,

t = Time in years.

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1 month will be equal to $\frac{1}{12}$ .

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$\$10=0.0025P$

$\frac{\$10}{0.0025}=\frac{0.0025P}{0.0025}$

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Therefore, to earn $10 in 1st month, the principal must be $4,000.

Now, we will check if an account of $2,500 can earn at least $10 interest in 1 month.

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Answer:

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Step-by-step explanation:

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