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Volgvan
3 years ago
15

Look at the image above: Could someone please do this for me

Mathematics
2 answers:
scoundrel [369]3 years ago
8 0

Answer:

the shapes below are similar because,

Step-by-step explanation:

36 divided by 4 is 9.

9 is also the length on shape 2.

(9x2) + (4x2) = 36

36 is also the area of shape 2

nata0808 [166]3 years ago
3 0

Answer:

I think it is the area and perimeter are the same

Step-by-step explanation: Shape 1: If the perimeter is 26. one side is 9. 26-18= 8. You divide that to get the measure of the other side which is 4. 9*4=36.          Shape 2: area is equal to 36, one side is for so the other side has to be 9. So the perimeter of shape 2 is 26 too.

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Last saturday, marissa walked her dog 1 1/2 miles. Sally walked her dog 2 times far. How many miles total did both girls walk th
andriy [413]

Answer:

4.5 miles

Step-by-step explanation:

7 0
3 years ago
If r(X)=2-x^2 and w(X)=X-2, what is the range of (w*r)(X)
slega [8]
The given function are
r(x) = 2 - x²    and     w(x) = x - 2
<span>(w*r)(x) can be obtained by multiplying the both function together
</span>
So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
            = 2x - x³ - 4 + 2x²

∴ <span>(w*r)(x) = -x³ + 2x² + 2x - 4
</span>

<span>It is a polynomial function with a domain equal to R
</span>
The range of <span>(w*r)(x) can be obtained by graphing the function
</span>
To graph (w*r)(x), we need to make a table between x and (w*r)(x)

See the attached figure which represents the table and the graph of <span>(w*r)(x)
</span>

As shown in the graph the range of <span>(w*r)(x) is (-∞,∞)
</span>

8 0
3 years ago
Read 2 more answers
Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I
dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

8 0
3 years ago
(2×-5) for ×=-3 and for ×=3.​
Brut [27]

Answer:

<h2>-11 and 1</h2>

Step-by-step explanation:

Put the values of x to the given expression:

for x = -3:

2(-3) - 5 = -6 - 5 = -11

for x = 3

2(3) - 5 = 6 - 5 = 1

6 0
3 years ago
The annual snowfall in city A is 58.7 inches. This is 12.5 inches more than six times the snowfall in city B. Find the annual sn
Lelechka [254]
The annual snowfall for city B is 7.7 inches. 
Since it is 12.5 inches more: 58.7 - 12.5 = 46.2
Since 46.2 is 6 times that of city B: 46.2 / 6 = 7.7


3 0
3 years ago
Read 2 more answers
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