Answer:
3/2 miles per hour
Step-by-step explanation:
How do I find miles per hour from 2 fractions? For Example: If I ran for 1/2 miles when It lasted 1/3 of an hour. Would It be 1/6?
Given data
distance= 1/2 miles
time= 1/3 hour
Speed= distance/time
Substitute
Speed= 1/2/1/3
Speed= 1/2*3/1
Speed= 3/2 miles per hour
Answer:
1) x = 15
Step-by-step explanation:
We use the Pythagorean thm for these questions. Where a and b are the legs (So order doesn't matter), and where c is the hypotenuse
1)
a² + b² = c²
9² + 12² = x²
81 + 144 = x²
x² = 225
You square root each side so you can get rid of the exponent on x.
x = 15
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750
Correct answer is C)</span>
The half of a cake has volume which can be divided by 3
Hmmm... a geometric sequence MUST have a fixed common ratio. If it is changing, then the sequence you are looking at might not be a geometric sequence at all. We'd need to see an example to be sure.
