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Damm [24]
2 years ago
10

A) Describe the congruence shortcut (postulate/theorem) that could be used to prove that ΔABC≅ΔDEF

Mathematics
1 answer:
bixtya [17]2 years ago
6 0

Answer:

A. By the Side-Side-Side (SSS) Congruence Theorem, ΔABC ≅ ΔDEF.

B. \overline{AB} \cong \overline{DE}

\overline{BC} \cong \overline{EF}

\overline{AC} \cong \overline{DF}

Step-by-step explanation:

a. From the diagram given, it shows that all three sides of ∆ABC are congruent to all the three corresponding sides of ∆DEF.

Therefore, by the Side-Side-Side (SSS) Congruence Theorem, ΔABC ≅ ΔDEF.

b. The sides that are congruent in the ∆s given that applies to the SSS Congruence Theorem are:

\overline{AB} \cong \overline{DE}

\overline{BC} \cong \overline{EF}

\overline{AC} \cong \overline{DF}

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2 years ago
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drek231 [11]

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In the question ,

it is given that ,

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