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Mazyrski [523]
2 years ago
13

Algebra llquestion a and b​

Mathematics
1 answer:
Tamiku [17]2 years ago
3 0

Answer:

40

Step-by-step explanation:

10=274

gy

fuo

469

30+10

40

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Martin bikes at a constant speed to a finish line that is 15 mi away. After 20 mins, he is 10 mi from the finish line. After 30
ankoles [38]

The answer is C. -0.25; the rate at which Martin's distance from the finish line changes per minute

5 0
2 years ago
An equivalent expression to a2/3
scoundrel [369]

Answer:

4/6  6/9  8/12  10/15 and so on, just multiply both the numerator and denominator by the same number and get your answer.

Step-by-step explanation:

6 0
3 years ago
Readings on a thermometer are normally distributed with a mean of 0C° and a standard deviation of 1.00. What is the probability
hichkok12 [17]

Given mean = 0 C and standard deviation = 1.00

To find probability that a random selected thermometer read less than 0.53, we need to find z-value corresponding to 0.53 first.

z= \frac{x-mean}{standard deviation}  = \frac{0.53-0}{1.00} = 0.53

So, P(x<0.53) = P(z<0.53) = 0.701944

Similarly P(x>-1.11)=P(z>-1.11) = 1-P(z<-1.11) = 0.8665

For finding probability for in between values, we have to subtract smaller one from larger one.

P(1.00<x<2.25) = P(1.00<z<2.25) = P(z<2.25)- P(z<1.00) = 0.9878 - 0.8413 = 0.1465

P(x>1.71) = P(z>1.71) = 1-P(z<1.71) = 1-0.9564 = 0.0436

P(x<-0.23 or x>0.23) = P(z<-0.23 or z>0.23)  =P(z<-0.23)+P(z>0.23) = 0.409+0.409 = 0.918

4 0
3 years ago
PLEASE ANSWER ILL MARK YOU AS THE BRAINLIEST
Solnce55 [7]

Answer:

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Step-by-step explanation:

7 0
3 years ago
One of the legs of a right triangle measures 9 cm and the other leg measures 11 cm.
ikadub [295]

Answer:

\boxed {\boxed {\sf 14.2 \ cm}}

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.

a^2+b^2=c^2

where <em>a</em> and<em> b</em> are the legs and <em>c</em> is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:

  • a= 9 cm
  • b= 11 cm

Substitute these values into the formula.

(9 \ cm)^{2}  +(11 \ cm)^{2} =c^{2}

Solve the exponents.

  • (9 cm)²= 9 cm*9 cm=81 cm²

81 \ cm^{2}  +(11 \ cm)^{2} =c^{2}

  • (11 cm)²= 11 cm*11 cm= 121 cm²

81 \ cm^{2}  +121 cm^{2} =c^{2}

Add the values on the left side.

202 \ cm^{2} =c^{2}

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

\sqrt {202 \ cm^{2} }=\sqrt{c^{2} }

\sqrt {202 \ cm^{2} }=c

14.2126704036 \ cm =c

We are told to round to the nearest tenth.

  • 14.2<u>1</u>26704036

The 1 in the hundredth place tells us to leave the 2 in the tenth place.

14.2 \ cm= c

The hypotenuse is equal to <u>14.2 centimeters.</u>

3 0
3 years ago
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