Answer: y=4
Step-by-step explanation:
In order to find y axis interception , you need to substitute the x=0 into your equation, by doing this you get 3*2^(0)+1 which is eventually equals to 4
Answer:
The equation should look something like this.
Be careful with your use between cubing and multiplying; Cubing is multiplying the number by itself multiple times, while multiplying is like repeated adding, yet much easier.
In this case, if it says triple, I highly recommend multiplying by 3, which is what I did, it only looks different because it is in parentheses.
What have we learned?
<h3>We learned how to write algebraic equations, and some further information on multiplying.</h3>
Answer:
nElements = 0;
for (int i = 0; i < a2d.length; i++)
nElements += a2d[i].length;
isRectangular = true;
for (int i = 1; i < a2d.length && isRectangular; i++)
if (a2d[i].length != a2d[0].length)
isRectangular = false;
Step-by-step explanation:
2 dimensional array is created and initialize element with 0. and the taking loop for 2 dimensional array .such as
n Elements = 0;
for (int i = 0; i < a2d.length; i++)
n Elements += a2d[i].length;
A boolean variable isRectangular and 2 dimensional array has been created if rectangle is true the take a2d.length and isRectangular less than i and intiliaze i with 1 then increment the i .It will give true value.
If rectangular is false then apply if statement and see if a2d[i] is not equal to a2d[0]
if (a2d[i].length != a2d[0].length)
isRectangular = false;
