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saul85 [17]
2 years ago
6

3(2x-4)=60 PLS HELP I HAVE A MATH TEST AND ITS DUE TODAY AND SHOW WORK PLS

Mathematics
1 answer:
boyakko [2]2 years ago
3 0
The answer: x = 12
Ok done. Thank to me :>

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A store buys 17 sweaters for $255 and sells them for $578. How much profit 1 point
ddd [48]
The answer is 243 is the answer to this question
4 0
2 years ago
karl can flip 3 water bottles in 1/8 of a minute at that rate how many bottles can we expect him to flip in 1 minute
lara [203]

Answer:

Step-by-step explanation:

x/1=3/(1/8)

x=3(8/1)=24 bottles per minute

6 0
3 years ago
Janelle went to the bank twice and withdrew a total of $40 from
Oduvanchick [21]

Answer:

20$ each visit

Step-by-step explanation

Divide 40 by 2 for her 2 visits to the bank

\frac{40}{2} = 20 \\

<em>Final Answer: </em>20

 

6 0
2 years ago
A.
koban [17]

Answer: It would be 4b+44

Step-by-step explanation:

This is the distributive property! so a(b+c)=ab+ac

In this case–4b+44!

6 0
2 years ago
Read 2 more answers
A random sample of 200 shoppers at a local grocery store found that 135 of the 200 sampled
VMariaS [17]

Using the z-distribution, as we are working with a proportion, it is found that samples of 937 should be taken.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

  • The estimate is of \pi = 0.675.
  • The margin of error is of M = 0.03.
  • 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

Then, we solve for n to find the minimum sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.675(0.325)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.675(0.325)}

\sqrt{n} = \frac{1.96\sqrt{0.675(0.325)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.675(0.325)}}{0.03}\right)^2

n = 936.4

Rounding up, it is found that samples of 937 should be taken.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
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