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weeeeeb [17]
3 years ago
11

If ex + e⁻¹= 2, then x =..

Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

\rm x = \dfrac{2e - 1}{ {e}^{2} }

Step-by-step explanation:

\rm Solve \:  for \:  x: \\  \rm \longrightarrow ex +  {e}^{ - 1}  = 2 \\  \\   \rm \longrightarrow e x +  \dfrac{1}{e}  = 2 \\  \\  \rm Subtract \:   \dfrac{1}{e} \:  from \:  both  \: sides: \\   \rm \longrightarrow e x  +  \dfrac{1}{e} -  \dfrac{1}{e}  = 2  -  \dfrac{1}{e}  \\  \\   \rm \longrightarrow ex =  \dfrac{2e}{e} -  \dfrac{1}{e}   \\  \\   \rm \longrightarrow ex =  \dfrac{2e - 1}{e}  \\  \\  \rm Divide \:  both  \: sides  \: by  \: e: \\   \rm \longrightarrow  \dfrac{ex}{e}  =  \dfrac{2e - 1}{e \times e}  \\  \\   \rm \longrightarrow x =  \dfrac{2e - 1}{ {e}^{2} }

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X-1=y what is the answer plz give me the answer
guajiro [1.7K]

Answer:

<h2>X = 0</h2><h2>Y = 1</h2>

First of all, observe that this is a line, since you can rewrite the equation as y−x+1=0 , which follows the pattern of the generic line ax+by+c=0 .

To draw a line you need two of its points, which you can connect.

To find two points, you can plug any value for one variable, and solve for the other.

For example, let's choose

x=0 . The equation becomes

0−1=y , and so y=−1 .

The first point is thus (0,−1).

Then, let's choose

x=1 . The equation becomes 1−1=y , and so y=0 . The first point is thus

(1,0).

Now you only need to draw the points

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Step-by-step explanation:

Hope it is helpful...

6 0
3 years ago
Solve for w. <br><br> 1/3w + 5/6w - 2 = -w
Scorpion4ik [409]

Answer: w=\frac{12}{13}

Step-by-step explanation:

To solve for w, we want to isolate the variable.

\frac{1}{3}w +\frac{5}{6}w-2=-w        [add both sides by 2 and w]

\frac{1}{3}w +\frac{5}{6}w+w=2           [convert to same denominator]

\frac{2}{6}w +\frac{5}{6}w+\frac{6}{6} w=2         [add]

\frac{13}{6} w=2                          [multiply both sides by 6/13]

w=\frac{12}{13}

Now we know that w=\frac{12}{13}.

6 0
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insens350 [35]

Answer:

Step-by-step explanation:

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