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weeeeeb [17]
3 years ago
11

If ex + e⁻¹= 2, then x =..

Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

\rm x = \dfrac{2e - 1}{ {e}^{2} }

Step-by-step explanation:

\rm Solve \:  for \:  x: \\  \rm \longrightarrow ex +  {e}^{ - 1}  = 2 \\  \\   \rm \longrightarrow e x +  \dfrac{1}{e}  = 2 \\  \\  \rm Subtract \:   \dfrac{1}{e} \:  from \:  both  \: sides: \\   \rm \longrightarrow e x  +  \dfrac{1}{e} -  \dfrac{1}{e}  = 2  -  \dfrac{1}{e}  \\  \\   \rm \longrightarrow ex =  \dfrac{2e}{e} -  \dfrac{1}{e}   \\  \\   \rm \longrightarrow ex =  \dfrac{2e - 1}{e}  \\  \\  \rm Divide \:  both  \: sides  \: by  \: e: \\   \rm \longrightarrow  \dfrac{ex}{e}  =  \dfrac{2e - 1}{e \times e}  \\  \\   \rm \longrightarrow x =  \dfrac{2e - 1}{ {e}^{2} }

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