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3 years ago

IF 30 Men Car do a piece of Work in 30 days the

Mathematics

2 answers:

liubo4ka [24]3 years ago

8 0

10 days because 30 men = 30 days, so in that logic 10 days = 10 men

kiruha [24]3 years ago

4 0

Answer:

let, the days for 10 men be x

30/10=x/30
900=10x
x=900/10
x=90

so 10 men can complete the same work in 90days.

Hope it helps.

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1.4 – 5.5 – 1.73 + 1.8 – 1.09 –5.12 –8.72 5.12 –1.66

Novay_Z [31]

We'll do two by two,
1.4 – 5.5= -4.1
– 1.73 + 1.8= 0.07
Leaving – 1.09,

You get 
=-4.1+ 0.07- 1.09
=-4.03-1.09
=-5.12

7 0

3 years ago

Given that rectangle LMNO with coordinates L(0,0), M(3,0), N(3,7), O(0,7), P is the midpoint of LM⎯⎯⎯, and Q is the midpoint of

Elina [12.6K]

The midpoint of a line divides the line into equal segments.

The option that proves PQ = LO is (a)

The given parameters are:

$\mathbf{L = (0,0)}$

$\mathbf{M = (3,0)}$

$\mathbf{N = (3,7)}$

$\mathbf{O = (0,7)}$

P is the midpoint of LM.

So, we have:

$\mathbf{P = \frac{LM}{2}}$

$\mathbf{P = (\frac{(0 +3}{2},\frac{0+0}{2})}$

$\mathbf{P = (\frac{3}{2},0)}$

Q is the midpoint of NO.

So, we have:

$\mathbf{Q = \frac{NO}{2}}$

$\mathbf{Q = (\frac{(3 +0}{2},\frac{7+7}{2})}$

$\mathbf{Q = (\frac{3}{2},7)}$

Distance PQ is calculated as follows:

$\mathbf{d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

This gives:

$\mathbf{PQ = \sqrt{(3/2 - 3/2)^2 + (0 - 7)^2}}$

$\mathbf{PQ = \sqrt{ 7^2}}$

$\mathbf{PQ = 7}$

Distance LO is calculated as follows:

$\mathbf{LO = \sqrt{(0 - 0)^2 + (0 - 7)^2}}$

$\mathbf{LO = \sqrt{ 7^2}}$

$\mathbf{LO=7}$

So, we have:

$\mathbf{PQ = 7}$

$\mathbf{LO=7}$

Thus:

$\mathbf{PQ = LO}$

Hence, the correct option is (a)

Read more about distance and midpoints at:

brainly.com/question/11231122

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2 years ago

On a coordinate plane, 5 squares are shown. Square L M N P has points (negative 3, 1), (negative 1, 1), (negative 1, negative 1)

hodyreva [135]

Answer:

the answer is 4

Step-by-step explanation:

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3 years ago

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Factor and show all work. 15^2y^2-x^3y+7

Ber [7]

(15^2)(y^2)−x^3+7=225y^2+−x^3+7
=−x^3+225y^2+7

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3 years ago

Assume running consumes 100 calories per mile. If you run 10-minute miles, what is your average power output, in watts, during a

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We are given with the rate of calories burnt out through running of 100 calories per mile. If 10 miles is ran, we get the total calories burnt is 100 calories per mile * 10 miles equal to 1000 calories. Power (watts) is equal to Joules per second. 1000 calories is equal to 4185.8 Joiules. In an hour run- the power is 69.76 Watts

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3 years ago