Answer:
2a^2b^3 ^3squareroot4a
Step-by-step explanation:
Answer:
your answer is -5,-10
Step-by-step explanation:
please mark brainliest
It is not necessary that the function decreasing over a given interval always be negative.
A function f(x) (value) decreases as x increases.
This does not mean that value of f(x) is negative.
It can have positive number as range.
p(x)= x-2
g(x)= 2x^3 + 3x^2 - 11x - 6
first we have to find the zero of the polynomial of x-2
p(x)= x-2 = 0
x=2
therefore,
p(x)= 2x^3 + 3x^2 - 11x - 6
p(2)= 2*2^3 + 3*2^2 - 11*2 - 6
= 2*8 + 3*4 - 11*2 - 6
= 16 + 12 - 22 - 6
= 28-28
= 0
Hope it helped u, ^_^.
Answer:
y=x-8 and y=-x+4
Step-by-step explanation:
The slopes of the lines can be anything, as long as they are the opposite reciprocals of each other. Then you can plug in the point for x and y to solve for b in both lines (for y=mx+b where m is the slope)
